javascript Javascript将时间字符串设置为日期对象
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Javascript set time string to date object
提问by Sarika.S
Please see the below code;
请看下面的代码；
var d = new Date();
var s = "01.00 AM";
d.setTime(s);
I know this code is wrong. Please give me the correct way to set the time. I have 12 hour time in string format in my hand.
我知道这段代码是错误的。请给我设置时间的正确方法。我手上有 12 小时的字符串格式时间。
The time will vary. Cannot know what will be the time earlier. Also it is 12 hour time. So it will be AM or PM
时间会有所不同。不知道什么时候会更早。也是12小时的时间。所以它将是 AM 或 PM
回答by thebreiflabb
You can parse the time with a regex, and set the hours and minutes accordingly:
您可以使用正则表达式解析时间，并相应地设置小时和分钟：
var d = new Date(),
s = "01.25 PM",
parts = s.match(/(\d+)\.(\d+) (\w+)/),
hours = /am/i.test(parts[3]) ? parseInt(parts[1], 10) : parseInt(parts[1], 10) + 12,
minutes = parseInt(parts[2], 10);
d.setHours(hours);
d.setMinutes(minutes);
alert(d);
Edit 1:As jaisonDavis pointed out, the original code will not work for AM or PM for 12.XX, which was an oversight since I never use 12-hour format myself, thinking it started at 00.00 which was wrong.
编辑 1：正如 jaisonDavis 指出的那样，原始代码不适用于 12.XX 的 AM 或 PM，这是一个疏忽，因为我自己从未使用过 12 小时格式，认为它是从 00.00 开始的，这是错误的。
The corrected code which handles these cases can be seen here:
处理这些情况的更正代码可以在这里看到：
var test, parts, hours, minutes, date,
d = (new Date()).getTime(),
tests = ['01.25 PM', '11.35 PM', '12.45 PM', '01.25 AM', '11.35 AM', '12.45 AM'],
i = tests.length,
timeReg = /(\d+)\.(\d+) (\w+)/;
for(; i-- > 0;) {
test = tests[i];
parts = test.match(timeReg);
hours = /am/i.test(parts[3]) ?
function(am) {return am < 12 ? am : 0}(parseInt(parts[1], 10)) :
function(pm) {return pm < 12 ? pm + 12 : 12}(parseInt(parts[1], 10));
minutes = parseInt(parts[2], 10);
date = new Date(d);
date.setHours(hours);
date.setMinutes(minutes);
console.log(test + ' => ' + date);
}回答by Travis Heeter
I'm late to the party, but I thought I'd share a funtion that doesn't use regex:
我参加聚会迟到了，但我想我会分享一个不使用正则表达式的功能：
function setDateTime(date, time) {
var index = time.indexOf("."); // replace with ":" for differently displayed time.
var index2 = time.indexOf(" ");
var hours = time.substring(0, index);
var minutes = time.substring(index + 1, index2);
var mer = time.substring(index2 + 1, time.length);
if (mer == "PM"){
hours = hours + 12;
}
date.setHours(hours);
date.setMinutes(minutes);
date.setSeconds("00");
return date;
}
回答by loyoliteabid
Using moment.jswill be the best solution.
使用moment.js将是最好的解决方案。
const fullDate = new Date();
// fullDate = Tue Dec 12 2017 11:18:30 GMT+0530 (IST) {}
const time = '01.00 AM';
const d = moment(fullDate).format('L'); // d = "12/12/2017"
const date = moment(d +' '+ time).format();
// date = "2017-12-12T01:00:00+05:30"
If you want convert moment date to js date
如果您想将时刻日期转换为 js 日期
const jsDate = moment(date).toDate();
回答by AnhSirk Dasarp
function getCurrentDate() {
var lDate = new Date();
var lDay = lDate.getDate();
var lMonth = lDate.getMonth() + 1;
var lYear = lDate.getFullYear();
if (lDay < 10) {
lDay = '0' + lDay
}
if (lMonth < 10) {
lMonth = '0' + lMonth
}
mCurrentDate = lYear + "-" + lMonth + "-" + lDay + "T00:00:00+05:30";
}
回答by phlare
I added a few things as an improvement to the accepted answer by @thebreiflabb to suit my use case and thought i'd share.
我添加了一些东西作为对@thebreilabb 接受的答案的改进，以适应我的用例，并认为我会分享。
if the regex is changed to timeReg = /(\d+)[\.|:](\d+)\s?(\w+)/;,
it'll handle a few other common cases.
如果正则表达式更改为timeReg = /(\d+)[\.|:](\d+)\s?(\w+)/;，它将处理其他一些常见情况。
namely:
即：
- using a colon instead of decimal point between hours and minutes
- allowing am/pm to immediately follow the time with no space
- 在小时和分钟之间使用冒号而不是小数点
- 允许 am/pm 立即跟随时间而没有空间
also, setting the seconds to 0 (since that was my main use case)
此外，将秒数设置为 0（因为这是我的主要用例）
the resulting code would be:
结果代码将是：
var test, parts, hours, minutes, date,
d = (new Date()).getTime(),
tests = ['01.25 PM', '01:25pm', '1:25 PM', '11.35 PM', '12.45 PM', '01.25 AM', '11.35 AM', '12.45 AM'],
i = tests.length,
timeReg = /(\d+)[\.|:](\d+)\s?(\w+)/;
for(; i-- > 0;) {
test = tests[i];
parts = test.match(timeReg);
hours = /am/i.test(parts[3]) ?
function(am) {return am < 12 ? am : 0}(parseInt(parts[1], 10)) :
function(pm) {return pm < 12 ? pm + 12 : 12}(parseInt(parts[1], 10));
minutes = parseInt(parts[2], 10);
date = new Date(d);
date.setHours(hours);
date.setMinutes(minutes);
date.setSeconds(0);
console.log(test + ' => ' + date);
}
