Laravel - 如何在不实例化对象的情况下调用静态函数
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Laravel - How to call static function without instantiate object
提问by boomdrak
Is there any way in Laravel (5.2) to call static and/or non-static function in a custom object without having to instantiate the referring object in all classes it is used?
在 Laravel (5.2) 中有什么方法可以在自定义对象中调用静态和/或非静态函数，而不必在它使用的所有类中实例化引用对象？
Example: I have class App\Helpers\Utilities.phpwith public function doBeforeTask()
示例：我有App\Helpers\Utilities.php公共功能的课程doBeforeTask()
I'm using this method in allot of classes within my project and it would be pretty if i could just call Utilities::doBeforeTask()or Utilities->doBeforeTask()without creating a instance of my Utilities object $obj = new Utilities();
我在我的项目中的分配类中使用此方法，如果我可以调用Utilities::doBeforeTask()或Utilities->doBeforeTask()不创建我的 Utilities 对象的实例，那就太好了$obj = new Utilities();
回答by Basit Munir
define your method as static method. and call it anywhere with following code:
将您的方法定义为静态方法。并使用以下代码在任何地方调用它：
Utilities::doBeforeTask();
Code structure of file App\Helpers\Utilities.php
App\Helpers\Utilities.php文件的代码结构
namespace App\Library;
class Utilities {
//added new user
public static function doBeforeTask() {
// ... you business logic.
}
}
回答by Parth kharecha
Define your method as a static method. and call it anywhere
将您的方法定义为静态方法。并在任何地方调用它
let's take an example
让我们举个例子
namespace App\Http\Utility;
class ClassName{
public static function methodName(){
// ... you business logic.
}
}
where you want to use specify the namespace
你想使用的地方指定命名空间
like this:
像这样：
use App\Http\Utility\ClassName;
ClassName::methodName();
Don't forget to run
别忘了奔跑
composer dump-autoload
回答by Frank Provost
Define static function
定义静态函数
class Foo
{
public static function staticFunction() {
return 'Hello World';
}
}
now call Foo::staticFunction()
现在调用 Foo::staticFunction()
回答by digout
If it's a method that you cannot change to static (i.e. it's a vendor file) then you can do this in PHP >= 5.4
如果它是一种您无法更改为静态的方法（即它是供应商文件），那么您可以在 PHP >= 5.4 中执行此操作
$something = (new Something)->foo("bar");
