Android setVisibility(GONE) 视图变得不可见但仍然占用空间
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setVisibility(GONE) view becomes invisible but still occupies space
提问by Dennis
I've got a view that is effectively is a button. Here is its XML layout (add_new.xml)
我有一个实际上是一个按钮的视图。这是它的 XML 布局 (add_new.xml)
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:tools="http://schemas.android.com/tools"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:orientation="horizontal">
<Button
android:id="@+id/buttonNew"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="@string/bText"
android:onClick="addNew"/>
</LinearLayout>
When I set its visibility to GONE like this
当我像这样将其可见性设置为 GONE 时
v = getActivity().getLayoutInflater().inflate(R.layout.add_new, null);
v.setVisibility(View.GONE);
it disappears but still occupies space. Like this: 
它消失了，但仍然占据着空间。像这样：
This button is a header in the ListView, which is defined by this xml:
这个按钮是 中的一个标题，ListView由这个 xml 定义：
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:id="@+id/porno" >
<ImageView
android:id="@+id/icon"
android:layout_width="30dp"
android:layout_height="40dp"
android:layout_marginLeft="4dp"
android:layout_marginRight="10dp"
android:layout_marginTop="4dp"
android:src="@drawable/ic_launcher">
</ImageView>
<TextView
android:id="@+id/label"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="@+id/label"
android:textSize="20dp" >
</TextView>
</LinearLayout>
And I dont want it to occupy an additional list item when its visibility is set to GONE. As it is stated in the documentation.
当它的可见性设置为 GONE 时，我不希望它占用额外的列表项。正如文档中所述。
GONE - This view is invisible, and it doesn't take any space for layout purposes.
GONE - 此视图是不可见的，并且不占用任何布局空间。
Any ideas on how to make it NOT occupy space?
关于如何使它不占用空间的任何想法？
Thanks, Dennis xx
谢谢，丹尼斯 xx
P.S. My listview is inside of a FoldersFragment ListFragmentand here is the xml of my MainActivity where FoldersFragment is presented
PS 我的列表视图位于 FoldersFragment 内ListFragment，这里是我的 MainActivity 的 xml，其中显示了 FoldersFragment
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:orientation="horizontal" >
<fragment
android:id="@+id/foldersFragment"
android:layout_width="200dip"
android:layout_height="match_parent"
class="com.example.fragments.FoldersFragment" >
</fragment>
<fragment
android:id="@+id/detailFragment"
android:layout_width="match_parent"
android:layout_height="match_parent"
class="com.example.fragments.DetailFragment" >
</fragment>
</LinearLayout>
采纳答案by noni
This is an Android bug in my opinion, we just fix this issue doing this:
在我看来，这是一个 Android 错误，我们只是通过以下方式解决此问题：
<FrameLayout android:layout_width="match_parent"
android:layout_height="wrap_content">
<LinearLayout android:id="@+id/layout_to_hide"
android:layout_width="match_parent"
android:layout_height="wrap_content">
//Put here your views
</LinearLayout>
</FrameLayout>
Just hide LinearLayout with id LAYOUT_TO_HIDEwith Visible.GONEand then root FrameLayout will collapse its height giving you a "hidden" with non-blank-space header.
只是隐藏的LinearLayout id为LAYOUT_TO_HIDE与Visible.GONE再根的FrameLayout会崩溃的高度给你一个“隐藏的”非空白空间标题。
回答by Jaguar
All replies in this thread are suggesting a new wrapper view, which comes at a cost. The correct way of hiding a view completely is to set margins to 0 while setting visibility to GONE. In this code sample, cardViewis the view I am trying to hide. The direct parent of cardViewis RecyclerView, that's why we are using RecyclerView.LayoutParams - remember to replace with the right layout params.
此线程中的所有回复都建议使用新的包装器视图，这是有代价的。完全隐藏视图的正确方法是将边距设置为 0，同时将可见性设置为GONE。在此代码示例中，cardView是我试图隐藏的视图。cardView的直接父级是 RecyclerView，这就是我们使用 RecyclerView.LayoutParams 的原因——记得用正确的布局参数替换。
if (cardView.getVisibility() != GONE) {
cardView.setVisibility(GONE);
RecyclerView.LayoutParams layoutParams = (RecyclerView.LayoutParams) cardView.getLayoutParams();
layoutParams.setMargins(0, 0, 0, 0);
cardView.setLayoutParams(layoutParams);
}
回答by Asad
set layout_widthand layout_heightto 0where you want to hide item, by doing this
设置layout_width并设置layout_height到0您想要隐藏项目的位置，通过执行此操作
//if item's parent layout is LinearLayout, change according to your item xml
holder.itemView.setLayoutParams(new LinearLayout.LayoutParams(0,0));
回答by Jayo2k
If this is stil needed, there is a great way to deal with it:
如果这仍然需要，有一个很好的方法来处理它：
parentView.removeView(childView);
here an example:
这里有一个例子：
final WhatEverLayout parentView, childView;
parentView = (WhatEverLayout)findViewById(R.id.parentView_xml);
childView =(WhatEverLayout)findViewById(R.id.childView_xml);
parentView.removeView(childView);
回答by kyorilys
This is my solution. Create a new layout file with name "special.xml", copy the code to the file.
这是我的解决方案。创建一个名为“special.xml”的新布局文件，将代码复制到文件中。
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:orientation="vertical"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:visibility="gone">
</LinearLayout>
Use condition to inflate the empty layoutinside the newview. Don't Use the view.setVisibility(View.GONE);.
使用条件来膨胀新视图内的空布局。不要使用view.setVisibility(View.GONE); .
if(true){
view=mInflater.inflate ( R.layout.special,parent, false );
}else{
view=mInflater.inflate(R.layout.normal,parent,false);
// The view that you want to be visible
}
回答by wanglugao
header_layout.xml:
header_layout.xml:
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:orientation="vertical"
android:layout_width="match_parent"
android:layout_height="match_parent">
<LinearLayout
android:id="@+id/mHeaderView"
android:orientation="vertical"
android:layout_width="match_parent"
android:layout_height="wrap_content">
<TextView
android:id="@+id/mNoHelpLayout"
android:layout_width="match_parent"
android:layout_height="176dip"
android:background="#ffffffff"
android:gravity="center"
/>
</LinearLayout>
</LinearLayout>
java code:
代码：
LayoutInflater mInflater =(LayoutInflater) getActivity().getSystemService(Context.LAYOUT_INFLATER_SERVICE);
View outerView = mInflater.inflate(R.layout.header_layout, null);
mHeaderView = (LinearLayout) outerView.findViewById(R.id.mHeaderView);
use mHeaderView.setVisiable() to control visiable not the outerView.setVisiable(). it works for me.
使用 mHeaderView.setVisiable() 来控制可见而不是 outerView.setVisiable()。这个对我有用。
回答by Jayo2k
What you can do is set an if statement, whenever the condition to set the visibility to "GONE", set the view as wrap content and your space will be free, I did it and it worked for a seekbar
您可以做的是设置一个 if 语句，每当将可见性设置为“GONE”的条件时，将视图设置为换行内容，您的空间将是免费的，我做到了，它适用于搜索栏
回答by murugan mani
If you want to show itemView
if (ItemBean.isShow())
{
holder.itemView.setVisibility(View.VISIBLE);
holder.itemView.setLayoutParams(new LinearLayout.LayoutParams(ViewGroup.LayoutParams.MATCH_PARENT, ViewGroup.LayoutParams.WRAP_CONTENT));
} else
{
holder.itemView.setLayoutParams(new LinearLayout.LayoutParams(0, 0));
holder.itemView.setVisibility(View.GONE);
}
回答by Mudit Khandelwal
You can use :
viewToHide?.postDelayed({ viewToHide?.visibility = View.GONE }, durationInMillis)
您可以使用 ：
viewToHide?.postDelayed({ viewToHide?.visibility = View.GONE }, durationInMillis)
回答by Prajwal W
A generic and easy solution is to avoid all thuse heck of code:
一个通用且简单的解决方案是避免所有这些代码：
You need to add a Container Layout or a Parent Layoutover your set of views that you want to hide. It can be anything like CardView or FrameLayout or etc.
您需要在要隐藏的视图集上添加容器布局或父布局。它可以是 CardView 或 FrameLayout 等任何东西。
Just it has to be a parent for that view that you want to hide. And you wont get all those white spaces. Coz it will consider the entire container to hide instead of considering individual views to HIDE thus, avoiding the white spaces.
只是它必须是您想要隐藏的视图的父级。你不会得到所有这些空白。因为它会考虑隐藏整个容器，而不是考虑隐藏单个视图，从而避免空白。
