Xcode：从 iOS TextField 发送数据到远程数据库的最简单方法
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Xcode: Easiest Way To Send Data From iOS TextField For Example To A Remote Database
提问by John
I currently have an online web hosted MySQL database with HostGator.com that currently stores user sign ups for a service of mine. Currently, the only way to store information in that database is from my online form on a website.
我目前在 HostGator.com 上有一个在线 Web 托管的 MySQL 数据库，该数据库当前存储用户注册我的服务。目前，在该数据库中存储信息的唯一方法是从我在网站上的在线表单。
My goal is to replicate that form on an iOS app by using textfields etc. What I need help figuring out is, how can I take the data input from the user on the iOS app, and send that information to the MySQL database. From what I found, there is no way to go from iOS straight to MySQL, so I would need to use PHP as well. However, how do I get that data from the iOS app to PHP so that I can send the data from PHP to the MySQL database? As well as, how I can I do the vice versa, meaning, if I wanted, how can I send a message back from PHP to the iOS app?
我的目标是通过使用文本字段等在 iOS 应用程序上复制该表单。我需要帮助弄清楚的是，如何在 iOS 应用程序上获取用户输入的数据，并将该信息发送到 MySQL 数据库。根据我的发现，无法从 iOS 直接转到 MySQL，因此我还需要使用 PHP。但是，如何将数据从 iOS 应用程序获取到 PHP，以便我可以将数据从 PHP 发送到 MySQL 数据库？以及，我如何反之亦然，这意味着，如果我愿意，如何将消息从 PHP 发送回 iOS 应用程序？
I have heard people suggest SQLite, but that appears to be a local database on the iOS which I do not need. I do not want to store anything locally on the app.
我听说有人建议使用 SQLite，但这似乎是我不需要的 iOS 本地数据库。我不想在应用程序上本地存储任何内容。
Thanks
谢谢
回答by futureelite7
You can just gather the data from a native form, then use a NSURLRequest / NSURLConnection to send the data to your php server page.
您可以只从本机表单收集数据，然后使用 NSURLRequest / NSURLConnection 将数据发送到您的 php 服务器页面。
//Example form with one php variable only. Use get URL argument notation to add more args.
NSString *rawStr = [NSString stringWithFormat:@"var=%@",textBox.text];
NSData *data = [rawStr dataUsingEncoding:NSUTF8StringEncoding];
NSURL *url = [NSURL URLWithString:@"http://myurl.com/script.php"];
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url];
[request setHTTPMethod:@"POST"];
[request setHTTPBody:data];
NSURLResponse *response;
NSError *err;
NSData *responseData = [NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&err];
NSLog(@"responseData: %@", responseData);
