C++ “错误：非静态成员引用必须相对于特定对象”是什么意思？
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what does "error : a nonstatic member reference must be relative to a specific object" mean?
提问by Oscar Yuandinata
int CPMSifDlg::EncodeAndSend(char *firstName, char *lastName, char *roomNumber, char *userId, char *userFirstName, char *userLastName)
{
...
return 1;
}
extern "C"
{
__declspec(dllexport) int start(char *firstName, char *lastName, char *roomNumber, char *userId, char *userFirstName, char *userLastName)
{
return CPMSifDlg::EncodeAndSend(firstName, lastName, roomNumber, userId, userFirstName, userLastName);
}
}
On line return CPMSifDlg::EncodeAndSendI have an error :
Error : a nonstatic member reference must be relative to a specific object.
在线return CPMSifDlg::EncodeAndSend我有一个错误：错误：非静态成员引用必须相对于特定对象。
What does it mean?
这是什么意思？
回答by Nawaz
EncodeAndSendis not a static function, which means it can be called on an instance of the class CPMSifDlg. You cannot write this:
EncodeAndSend不是静态函数，这意味着它可以在类的实例上调用CPMSifDlg。你不能这样写：
CPMSifDlg::EncodeAndSend(/*...*/); //wrong - EncodeAndSend is not static
It should rather be called as:
它应该被称为：
CPMSifDlg dlg; //create instance, assuming it has default constructor!
dlg.EncodeAndSend(/*...*/); //correct
回答by Rohit Vipin Mathews
Only static functions are called with class name.
只使用类名调用静态函数。
classname::Staicfunction();
Non static functions have to be called using objects.
必须使用对象调用非静态函数。
classname obj;
obj.Somefunction();
This is exactly what your error means. Since your function is non static you have to use a object reference to invoke it.
这正是您的错误的含义。由于您的函数是非静态的，因此您必须使用对象引用来调用它。
回答by iammilind
CPMSifDlg::EncodeAndSend()method is declared as non-staticand thus it must be called using an object of CPMSifDlg. e.g.
CPMSifDlg::EncodeAndSend()方法被声明为非static，因此必须使用 的对象调用它CPMSifDlg。例如
CPMSifDlg obj;
return obj.EncodeAndSend(firstName, lastName, roomNumber, userId, userFirstName, userLastName);
If EncodeAndSenddoesn't use/relate any specifics of an object (i.e. this) but general for the class CPMSifDlgthen declare it as static:
如果EncodeAndSend不使用/关联对象的任何细节（即this）但一般用于class CPMSifDlg然后将其声明为static：
class CPMSifDlg {
...
static int EncodeAndSend(...);
^^^^^^
};
