Java 为任何整数输入参数设置模拟返回值
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原文地址: http://stackoverflow.com/questions/19155369/
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set mock return value for any integer input parameter
提问by
when(candidateService.findById(1)).thenReturn(new Candidate());
I want to extend this behaviour for any Integer(not necessarily for 1)
我想为任何整数扩展此行为（不一定为 1）
If I wrire
如果我写
when(candidateService.findById( any(Integer.class) )).thenReturn(new Candidate());
I have compilation error
我有编译错误
The method findById(Integer) in the type CandidateService is not applicable for the arguments (Matcher)
CandidateService 类型中的 findById(Integer) 方法不适用于参数 (Matcher)
UPDATE
更新
imports:
进口：
import static org.junit.Assert.assertEquals;
import static org.mockito.Matchers.anyInt;
import static org.mockito.Matchers.anyString;
import static org.mockito.Mockito.mock;
import static org.mockito.Mockito.times;
import static org.mockito.Mockito.verify;
import static org.mockito.Mockito.when;
import static org.springframework.test.web.servlet.result.MockMvcResultMatchers.status;
import java.util.ArrayList;
import java.util.HashSet;
import org.junit.Before;
import org.junit.Test;
import org.junit.runner.RunWith;
import org.mockito.InjectMocks;
import org.mockito.Mock;
import org.mockito.MockitoAnnotations;
采纳答案by Ernestas Kardzys
Try anyInt():
试试 anyInt()：
when(candidateService.findById(anyInt())).thenReturn(new Candidate());
For example I have anyLong() in my project:
例如，我的项目中有 anyLong()：
when(dao.getAddress(anyLong())).thenReturn(Arrays.asList(dto));
EDIT: You must import:
编辑：您必须导入：
import static org.mockito.Matchers.anyInt;
