Java 配置 Jackson 反序列化单引号（无效）JSON
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Configure Hymanson to deserialize single quoted (invalid) JSON
提问by Pipalayan Nayak
I am a newbie to using Hymanson library.
我是使用 Hymanson 库的新手。
I am trying to do this [see below], and it is throwing error.
我正在尝试这样做 [见下文]，但它抛出错误。
String x="{'candidateId':'k','candEducationId':1,'activitiesSocieties':'Activities for cand1'}";
ObjectMapper mapper = new ObjectMapper();
try {
JsonNode df=mapper.readValue(x,JsonNode.class);
int i=0;
} catch .....
Exception:
例外：
org.codehaus.Hymanson.JsonParseException: Unexpected character (''' (code 39)): was expecting double-quote to start field name at [Source: java.io.StringReader@1afd1810; line: 1, column: 3] at org.codehaus.Hymanson.JsonParser._constructError(JsonParser.java:1291)
org.codehaus.Hymanson.JsonParseException: Unexpected character (''' (code 39)): was expecting double-quote to start field name at [Source: java.io.StringReader@1afd1810; line: 1, column: 3] at org.codehaus.Hymanson.JsonParser._constructError(JsonParser.java:1291)
While the same thing works if I replace the single quote(') with double quote(").
如果我用双引号（“）替换单引号（'），同样的事情也会起作用。
采纳答案by Programmer Bruce
It's not valid JSON, but you can tell Hymanson to allow it. Here's how.
它不是有效的 JSON，但您可以告诉 Hymanson 允许它。就是这样。
String x = "{'candidateId':'k','candEducationId':1,'activitiesSocieties':'Activities for cand1'}";
ObjectMapper mapper = new ObjectMapper();
mapper.configure(JsonParser.Feature.ALLOW_SINGLE_QUOTES, true);
JsonNode df = mapper.readValue(x, JsonNode.class);
System.out.println(df.toString());
// output: {"candidateId":"k","candEducationId":1,"activitiesSocieties":"Activities for cand1"}
回答by Mark Elliot
Strings in JSON may only be specified using double quotes ("), notsingle quotes ('), this is the reason for your error; use double quotes.
JSON 中的字符串只能使用双引号 ( ")指定，而不是单引号 ( ')，这是您出错的原因；使用双引号。
Here's the pipe diagram that specifies valid JSON strings (note they may only be encapsulated with double quotes!)
这是指定有效 JSON 字符串的管道图（注意它们只能用双引号封装！）
(source: json.org)
（来源：json.org）
(See json.orgfor a complete specification of JSON.)
（有关JSON 的完整规范，请参阅json.org。）
回答by user2918934
This is the way it works in my case:
这是它在我的情况下的工作方式：
var jsonString ='{"it":"Stati Uniti d'America"}';
jsonString =jsonString.replace("'", "\\u0027");
