java 减去两个 Long 值
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Subtracting two Long values
提问by Me123
Why do I get error when I run the code below? How can I fix this? I want to System.out.print(hi-hello);
为什么我在运行下面的代码时会出错？我怎样才能解决这个问题？我想要System.out.print(hi-hello);
Long hello = 43;
Long hi = 3523;
public class HelloWorld{
public static void main(String[] args){
System.out.print(hi-hello);
}
}
采纳答案by ΦXoc? ? Пepeúpa ツ
Because hiand loware declared as LONGobjects, they must be either declared as literal by adding the L at the end or use the Long class
因为hi和low被声明为LONG对象，所以它们必须要么通过在末尾添加 L 来声明为文字，要么使用 Long 类
public class HelloWorld {
public static void main(String[] args) {
Long hello = 43L;
Long hi = 3523L;
System.out.print(hi-hello);
}
}
回答by YCF_L
Your attribute declaration and init should be inside your class :
你的属性声明和 init 应该在你的类中：
public class HelloWorld{
Long hello = 43;
Long hi = 3523;
Not out side for that you don't get correct result :
不是因为你没有得到正确的结果：
and your Long is not correct format it should be like this :
并且您的 Long 格式不正确，它应该是这样的：
Long hello = 43L;
Long hi = 3523L;
And when you are calling your attribute in a static method then you should to make them static, so your program should look like this :
当您在静态方法中调用您的属性时，您应该将它们设为静态，因此您的程序应如下所示：
public class HelloWorld
{
static Long hello = 43L;
static Long hi = 3523L;
public static void main(String[] args)
{
System.out.print(hi-hello);
}
}
This will print:
这将打印：
3480
NOTE
笔记
Like @EJP said in the comment :
就像@EJP 在评论中所说的：
When a number is too large to be represented by an int, it must be explicitly declared as a long by adding an L:
long n = 9876543210L;
当一个数字太大而无法用 int 表示时，必须通过添加 L 将其显式声明为 long：
long n = 9876543210L;
回答by Yiheng Jiang
longsdoes not use normal operators like +or -, instead, you need to use Long.sum(long l1, l2).
longs不使用像+或-这样的普通运算符，相反，您需要使用Long.sum(long l1, l2).
I'm not sure if there's other ways to do it, but this is what I use.
我不确定是否还有其他方法可以做到，但这就是我使用的方法。
