如何从 Java servlet 中抛出 404 错误？
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How do I throw a 404 error from within a java servlet?
提问by Kyle
How do I throw a 404 error from within a java servlet? My web.xml already specifies what page to show when there is a 404, how do I throw a 404 from within a servlet?
如何从 Java servlet 中抛出 404 错误？我的 web.xml 已经指定了出现 404 时要显示的页面，如何从 servlet 中抛出 404？
采纳答案by Ladlestein
The Servlet API gives you a method to send a 404 or any other HTTP status code. It's the sendError method of HttpServletResponse:
Servlet API 为您提供了一种发送 404 或任何其他 HTTP 状态代码的方法。这是 HttpServletResponse 的 sendError 方法：
public void doGet(HttpServletRequest request, HttpServletResponse response) {
response.sendError(HttpServletResponse.SC_NOT_FOUND);
}
回答by stacker
In your doGetor doPostmethod you have a parameter HttpServletResponse res
在您的doGetordoPost方法中，您有一个参数HttpServletResponse res
404 is a status code which can be set by:
404 是一个状态码，可以通过以下方式设置：
res.setStatus(HttpServletResponse.SC_NOT_FOUND);
回答by Aravinthan K
For adding Request URL with 404 use this below code
要使用 404 添加请求 URL，请使用以下代码
public void doGet(HttpServletRequest request, HttpServletResponse response) {
response.sendError(HttpServletResponse.SC_NOT_FOUND, request.getRequestURI());
}
