C# 将 xml 转换为排序字典
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convert xml to sorted dictionary
提问by raklos
i have an xml file similar to this:
我有一个与此类似的 xml 文件：
<?xml version="1.0" encoding="UTF-8"?>
<data>
<resource key="123">foo</resource>
<resource key="456">bar</resource>
<resource key="789">bar</resource>
</data>
i want to put this into a Dictionary (sorted) as key value pairs. i.e: 123:foo, 456:bar...etc
我想把它作为键值对放入字典（排序）中。即：123:foo, 456:bar...等
the keys are unknown.
钥匙是未知的。
how can i do this?
我怎样才能做到这一点？
采纳答案by gk.
Try this,
尝试这个，
string s = "<data><resource key=\"123\">foo</resource><resource key=\"456\">bar</resource><resource key=\"789\">bar</resource></data>";
XmlDocument xml = new XmlDocument();
xml.LoadXml(s);
XmlNodeList resources = xml.SelectNodes("data/resource");
SortedDictionary<string,string> dictionary = new SortedDictionary<string,string>();
foreach (XmlNode node in resources){
dictionary.Add(node.Attributes["key"].Value, node.InnerText);
}
回答by Johnno Nolan
This looks like a job for Linq to Xml
这看起来像是 Linq to Xml 的工作
static void Main(string[] args)
{
XDocument yourDoc = XDocument.Load("the.xml");
var q = from c in yourDoc.Descendants("resource")
orderby (int) c.Attribute("key")
select c.Attribute("key").Value + ":" + c.Value;
foreach (string s in q)
Console.WriteLine(s);
Console.ReadLine();
}
回答by Chris Dale
I would do this with XSLT transformation. Do you need to do the job with C#? If not you can simply make a XSLT document which parses through all resource tags and outputs key:value sorted out for you. Very easy accomplished. Is this a solution you want?
我会用 XSLT 转换来做到这一点。你需要用 C# 来完成这项工作吗？如果没有，您可以简单地制作一个 XSLT 文档，该文档解析所有资源标签并输出为您整理的键：值。很容易实现。这是您想要的解决方案吗？
回答by Robert Rossney
This is actually easier without using Linq and just using an XmlDocument:
这实际上更容易不使用 Linq 而只使用一个XmlDocument：
SortedDictionary<string, string> myDict = new SortedDictionary<string, string>();
foreach (XmlElement e in myXmlDocument.SelectNodes("/data/resource"))
{
myDict.Add(e.GetAttribute("key"), e.Value);
}
回答by Michael Damatov
Use LINQ:
使用 LINQ：
Load the document XDocument.Loador XDocument.Parse:
装入文件XDocument.Load或XDocument.Parse：
var xml = XDocument.Load(...);
Iterate through the ordered sequence:
遍历有序序列：
var sequence = from e in xml.Root.Elements()
let key = (string)e.Attribute("key")
order by key
select new {
Key = key,
Value = (string)e
};
