Python ValueError：未转换的数据仍然存在：02:05
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/20327937/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
ValueError: unconverted data remains: 02:05
提问by 4m1nh4j1
I have some dates in a json files, and I am searching for those who corresponds to today's date :
我在 json 文件中有一些日期，我正在搜索与今天日期相对应的日期：
import os
import time
from datetime import datetime
from pytz import timezone
input_file = file(FILE, "r")
j = json.loads(input_file.read().decode("utf-8-sig"))
os.environ['TZ'] = 'CET'
for item in j:
lt = time.strftime('%A %d %B')
st = item['start']
st = datetime.strptime(st, '%A %d %B')
if st == lt :
item['start'] = datetime.strptime(st,'%H:%M')
I had an error like this :
我有这样的错误：
File "/home/--/--/--/app/route.py", line 35, in file.py
st = datetime.strptime(st, '%A %d %B')
File "/usr/lib/python2.7/_strptime.py", line 328, in _strptime
data_string[found.end():])
ValueError: unconverted data remains: 02:05
Do you have any suggestions ?
你有什么建议吗 ？
采纳答案by Maxime Lorant
The value of stat st = datetime.strptime(st, '%A %d %B')line something like 01 01 2013 02:05and the strptimecan't parse this. Indeed, you get an hour in addition of the date... You need to add %H:%Mat your strptime.
statst = datetime.strptime(st, '%A %d %B')行的值类似于01 01 2013 02:05并且strptime无法解析此内容。实际上，除了日期之外，您还有一个小时......您需要%H:%M在您的 strptime添加。
回答by Martijn Pieters
You have to parse allof the input string, you cannot just ignore parts.
您必须解析所有输入字符串，不能只是忽略部分。
from datetime import date, datetime
for item in j:
st = datetime.strptime(item['start'], '%A %d %B %H:%M')
if st.date() == date.today():
item['start'] = st.time()
Here, we compare the date to today's date by using more datetimeobjects instead of trying to use strings.
在这里，我们通过使用更多datetime对象而不是尝试使用字符串来将日期与今天的日期进行比较。
The alternative is to only pass in partof the item['start']string (splitting out just the time), but there really is no point here, not when you could just parse everything in one step first.
另一种方法是仅通过部分中的item['start']字符串（分裂出去只是时间），但实在是没有点在这里，而不是当你可以只解析一切都在一步第一。
回答by 4m1nh4j1
Well it was very simple. I was missing the format of the date in the json file, so I should write :
嗯，这很简单。我错过了 json 文件中日期的格式，所以我应该写：
st = datetime.strptime(st, '%A %d %B %H %M')
because in the json file the date was like :
因为在 json 文件中，日期是这样的：
"start": "Friday 06 December 02:05",
回答by anjaneyulubatta505
Best answer is to use the from dateutil import parser.
最佳答案是使用from dateutil import parser.
usage:
用法：
from dateutil import parser
datetime_obj = parser.parse('2018-02-06T13:12:18.1278015Z')
print datetime_obj
# output: datetime.datetime(2018, 2, 6, 13, 12, 18, 127801, tzinfo=tzutc())
回答by Vishal Kanaujia
timeobj = datetime.datetime.strptime(my_time, '%Y-%m-%d %I:%M:%S')
File "/usr/lib/python2.7/_strptime.py", line 335, in _strptime
data_string[found.end():])
ValueError: unconverted data remains:
In my case, the problem was an extra space in the input date string. So I used strip()and it started to work.
就我而言，问题是输入日期字符串中有一个额外的空格。所以我使用了strip()它并开始工作。
