bash linux + 在目录下的文件中查找单词但很快
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linux + find word in file under directory but quickly
提问by yael
I have the following command
我有以下命令
find /var -type f -exec grep "param1" {} \; -print
With this command I can find the param1 string in any file under /var
使用此命令，我可以在 /var 下的任何文件中找到 param1 字符串
but the time that it take for this is very long.
但这需要很长时间。
I need other possibility to find string in file but much more faster then my example
我需要在文件中找到字符串的其他可能性，但比我的例子要快得多
THX
谢谢
yael
耶尔
回答by Bella
回答by yabt
Take a look at the -l option to the grep command for a speed boost. To speed up the find command use:
查看 grep 命令的 -l 选项以提高速度。要加速 find 命令，请使用：
find ... -exec sh -c '...' arg0 '{}' +
# grep ... -l: print files with matches, but stop scanning the file on the first match
grep -lsr "param1" /var
find /var -type f -exec sh -c 'grep -ls "param1" "$@"' arg0 '{}' +
find /var -type f -exec sh -c 'grep -ls "grep "param1" $(locate -r '^/var')
" "$@"' "param1" '{}' +
回答by krico
You can use locate's index (if you don't depend on files that are added/removed)
您可以使用 locate 的索引（如果您不依赖于添加/删除的文件）
find /var -type f | xargs grep "param1"
回答by Noufal Ibrahim
grep -r "param1" /var
would be slightly faster (no process spawning for each file)
会稍微快一点（每个文件都不会产生进程）
##代码##would be slightly more so I think.
所以我想会稍微多一点。
回答by UncleZeiv
Try also using ack, which is "better than grep" in most cases. Among its features the ability to ignore typical garbage files by default (such as .svn or .git directories, core dumps, backup files), the ability to use a large set of predefined file classes, nice output formatting.
也尝试使用 ack，它在大多数情况下“比 grep 好”。它的特点之一是能够默认忽略典型的垃圾文件（例如 .svn 或 .git 目录、核心转储、备份文件）、使用大量预定义文件类的能力、良好的输出格式。
回答by the wanderer
some of these command optimizations are helpful, but the biggest jump in speed I got from grepping 2 million files was to use a SSD Hard drive. Same queries took 1/5 of the time.
其中一些命令优化很有帮助，但我从 grep 200 万个文件中获得的最大速度飞跃是使用 SSD 硬盘。相同的查询花费了 1/5 的时间。
