如何使用 jquery/javascript 检查当前时间是否在工作日的特定范围内？
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How to check if current time falls within a specific range on a week day using jquery/javascript?
提问by kranthi
When a user visits a page I need to check if the current time falls between 9:00 am and 5:30pm on a weekday and display something using jquery/javascript.But I am not sure how can check that.
当用户访问页面时，我需要检查当前时间是否在工作日的上午 9:00 到下午 5:30 之间，并使用 jquery/javascript 显示一些内容。但我不确定如何检查。
Could someone please help?
有人可以帮忙吗？
Thanks
谢谢
回答by jabclab
This should hopefully help:
这应该会有所帮助：
function checkTime() {
var d = new Date(); // current time
var hours = d.getHours();
var mins = d.getMinutes();
var day = d.getDay();
return day >= 1
&& day <= 5
&& hours >= 9
&& (hours < 17 || hours === 17 && mins <= 30);
}
回答by John Strickler
Using the current time you could do something like this:
使用当前时间，您可以执行以下操作：
var now = new Date(),
day = now.getDay(),
hours = now.getHours();
//Check if day is Mon-Fri
if(0 < day < 6) {
//check between 9am and 5pm
if(9 <= hours <= 17) {
if(hours !== 17 || now.getMinutes() <= 30) {
//your jQuery code here
}
}
}
回答by André Al?ada Padez
var now = new Date();
var dayOfWeek = now.getDay();
if(dayOfWeek > 0 && dayOfWeek < 6){
//falls on a weekday
if (now.getHours() > 9 && (now.getHours() < 17 && now.getMinutes() < 30)) {
//it's in schedule
}
}
回答by Ray Xiao
Just added two cents to the hour checking...
只是在小时检查中增加了两美分......
I personally think that a better way would be to check if is in the range of a:b--c:d...
我个人认为更好的方法是检查是否在 a:b--c:d 的范围内...
// check if h:m is in the range of a:b-c:d
// does not support over-night checking like 23:00-1:00am
function checkTime (h,m,a,b,c,d){
if (a > c || ((a == c) && (b > d))) {
// not a valid input
} else {
if (h > a && h < c) {
return true;
} else if (h == a && m >= b) {
return true;
} else if (h == c && m <= d) {
return true;
} else {
return false;
}
}
}回答by gprathour
I had a requirement where I needed to find if time in one date object lies within other two. (Date didn't matter, instead only time).
我有一个要求，我需要找出一个日期对象中的时间是否在其他两个对象中。（日期无关紧要，而只是时间）。
I did it this way, I thought it might help someone.
我是这样做的，我认为它可能会帮助某人。
/*
* d, start and end all are Date objects.
*/
const checkIfTimeIsInRange = (d, start, end) => {
if (start.getHours() < d.getHours() && d.getHours() < end.getHours()) {
return true;
} else if (start.getHours() == d.getHours()) {
if (d.getHours() == end.getHours()) {
if(start.getMinutes() <= d.getMinutes() && d.getMinutes() <= end.getMinutes()) {
return true
} else {
return false
}
} else if(start.getMinutes() <= d.getMinutes()) {
return true
} else {
return false
}
} else if (d.getHours() == end.getHours()) {
if(d.getMinutes() <= end.getMinutes()) {
return true
} else {
return false
}
} else {
return false
}
}
P.S. Any improvements, suggestions are welcome.
PS任何改进，欢迎提出建议。
回答by Himanshu Saini
document.getElementById('tmp_button-48523').addEventListener('click', function() {
let d = new Date();
let localTime = d.getTime();
let localOffset = d.getTimezoneOffset() * 60000;
let utc = localTime + localOffset;
let target_offset = -7;//PST from UTC 7 hours behind right now, will need to fix for daylight
let los_angles = utc+(3600000*target_offset);
nd = new Date(los_angles);
let current_day = nd.getDay();
let hours = nd.getHours();
let mins = nd.getMinutes();
alert("los_angles time is " + nd.toLocaleString());
alert("Day is "+current_day);
if(current_day==2 && hours >= 14 && hours <=15 )
if(hours!=15 && mins >= 32)
fbq('track', 'LT-Login');
}, false);
function fbq(p1,p2){
alert(p1);
}<button id="tmp_button-48523">
Click me!
</button>