java Jersey/Jackson：如何捕获 json 映射异常？
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Jersey/Hymanson: how to catch json mapping exception?
提问by Neel
I would like to catch json mapping exception in my restful service in case input json is not valid.
如果输入 json 无效，我想在我的 Restful 服务中捕获 json 映射异常。
It throws org.codehaus.Hymanson.map.JsonMappingException, but I don't how to or where to catch this exception. I want to catch this exception and send back appropriate error response.
它 throws org.codehaus.Hymanson.map.JsonMappingException，但我不知道如何或在哪里捕获此异常。我想捕获此异常并发回适当的错误响应。
@JsonInclude(JsonInclude.Include.NON_NULL)
@Generated("org.jsonschema2pojo")
@JsonPropertyOrder({
"name",
"id"
})
public class Customer {
@JsonProperty("name")
private String name;
@JsonProperty("id")
private String id;
<setter/getter code>
}
public class MyService {
@POST
@Consumes(MediaType.APPLICATION_JSON)
public final Response createCustomer(@Context HttpHeaders headers,
Customer customer) {
System.out.println("Customer data: " + customer.toString());
return Response.ok("customer created").build();
}
}
Everything works fine, but if json body is not well formed then it throws JsonMappingExceptionexception. I want to catch this exception.
一切正常，但如果 json 主体格式不正确，则会引发JsonMappingException异常。我想捕捉这个异常。
回答by itzg
What finally worked for me was to declare an ExceptionMapperprovider for JsonMappingException, such as
最终对我有用的是声明一个ExceptionMapper提供程序JsonMappingException，例如
import org.codehaus.Hymanson.map.JsonMappingException;
import org.springframework.stereotype.Component;
import javax.ws.rs.core.Response;
import javax.ws.rs.ext.ExceptionMapper;
import javax.ws.rs.ext.Provider;
@Component
@Provider
public class JsonMappingExceptionMapper implements ExceptionMapper<JsonMappingException> {
@Override
public Response toResponse(JsonMappingException exception) {
return Response.status(Response.Status.BAD_REQUEST).build();
}
}
