C# 从 RGB 整数转换为十六进制
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Converting from RGB ints to Hex
提问by Toadums
What I have is R:255 G:181 B:178, and I am working in C# (for WP8, to be more specific)
我拥有的是 R:255 G:181 B:178，我正在使用 C#（对于 WP8，更具体地说）
I would like to convert this to a hex number to use as a color (to set the pixel color of a WriteableBitmap). What I am doing is the following:
我想将其转换为十六进制数以用作颜色（设置 WriteableBitmap 的像素颜色）。我正在做的是以下内容：
int hex = (255 << 24) | ((byte)R << 16) | ((byte)G << 8) | ((Byte)B<<0);
But when I do this, I just get blue.
但是当我这样做时，我只会变蓝。
Any ideas what I am doing wrong?
任何想法我做错了什么？
Also, to undo this, to check the RGB values, I am going:
另外，要撤消此操作，检查 RGB 值，我将：
int r = ((byte)(hex >> 16)); // = 0
int g = ((byte)(hex >> 8)); // = 0
int b = ((byte)(hex >> 0)); // = 255
采纳答案by NoPyGod
Try the below:
试试下面的：
using System.Drawing;
Color myColor = Color.FromArgb(255, 181, 178);
string hex = myColor.R.ToString("X2") + myColor.G.ToString("X2") + myColor.B.ToString("X2");
回答by Andreas
You can use a shorter string format to avoid string concatenations.
您可以使用较短的字符串格式来避免字符串连接。
string.Format("{0:X2}{1:X2}{2:X2}", r, g, b)
回答by huysentruitw
Using string interpolation, this can be written as:
使用字符串插值，这可以写成：
$"{r:X2}{g:X2}{b:X2}"
回答by Nelson Martins
Greetings fellow humans,
问候人类同胞，
//Red Value
int integerRedValue = 0;
//Green Value
int integerGreenValue = 0;
//Blue Value
int integerBlueValue = 0;
string hexValue = integerRedValue.ToString("X2") + integerGreenValue.ToString("X2") + integerBlueValue.ToString("X2");
