在 javax.json.spi.JsonProvider.provider(JsonProvider.java:97) 中找不到提供程序 org.glassfish.json.JsonProviderImpl

Provider org.glassfish.json.JsonProviderImpl not found at javax.json.spi.JsonProvider.provider(JsonProvider.java:97)

提问by Shaurya Manhar

How to run Java API for JSON Processing(JSR 374) in eclipse?

I am trying to parse JSON string to JsonParser(javax.json.stream.JsonParser). Also added javax.json-api-1.0.jar in the build path. At runtime, there is an exception. My code is

如何在 Eclipse 中为 JSON 处理（JSR 374）运行 Java API？

我正在尝试将 JSON 字符串解析为 JsonParser(javax.json.stream.JsonParser)。还在构建路径中添加了 javax.json-api-1.0.jar。在运行时，有一个例外。我的代码是

import java.io.StringReader;
import javax.json.Json;
import javax.json.JsonReader;
import javax.json.JsonStructure;
import javax.json.stream.JsonParser;
import javax.json.stream.JsonParser.Event;
import javax.json.JsonReader;
import javax.json.JsonStructure;
import javax.json.stream.JsonParser;
import javax.json.stream.JsonParser.Event;
public class jsonnn {
public class jsonnn {
public static void main(String[] args) {
        // Parse back
        final String result = "{\"name\":\"Falco\",\"age\":3,\"bitable\":false}";
        final JsonParser parser = Json.createParser(new StringReader(result));
        String key = null;
        String value = null;
        while (parser.hasNext()) {
            final Event event = parser.next();
            switch (event) {
            case KEY_NAME:
                key = parser.getString();
                System.out.println(key);
                break;
            case VALUE_STRING:
                value = parser.getString();
                System.out.println(value);
                break;
            }
        }
        parser.close();
    }
}

And the exception is

例外是

Exception in thread "main" javax.json.JsonException: Provider org.glassfish.json.JsonProviderImpl not found
at javax.json.spi.JsonProvider.provider(JsonProvider.java:97)
at javax.json.Json.createParser(Json.java:90)
at jsonnn.main(jsonnn.java:14)
Caused by: java.lang.ClassNotFoundException: org.glassfish.json.JsonProviderImpl
at java.net.URLClassLoader.findClass(Unknown Source)
at java.lang.ClassLoader.loadClass(Unknown Source)
at sun.misc.Launcher$AppClassLoader.loadClass(Unknown Source)
at java.lang.ClassLoader.loadClass(Unknown Source)
at java.lang.Class.forName0(Native Method)
at java.lang.Class.forName(Unknown Source)
at javax.json.spi.JsonProvider.provider(JsonProvider.java:94)
... 2 more

回答by Mike

You're developing against an API and have no implementation for that API. You need to make sure you have an implementation of the JSON-P specification to actually run the code you're trying to use.

您正在针对 API 进行开发，并且没有针对该 API 的实现。您需要确保拥有 JSON-P 规范的实现才能实际运行您尝试使用的代码。

In the JSR 374 official website Getting Started guide, it shows that you need twoMaven dependencies - one for the API and one for the reference implementation - before you can use JSON-P 1.1:

在JSR 374 官网 Getting Started guide 中，它显示您需要两个Maven 依赖项 - 一个用于 API，一个用于参考实现 - 才能使用 JSON-P 1.1：

<dependency>
    <groupId>javax.json</groupId>
    <artifactId>javax.json-api</artifactId>
    <version>1.1</version>
</dependency>

<dependency>
    <groupId>org.glassfish</groupId>
    <artifactId>javax.json</artifactId>
    <version>1.1</version>
</dependency>

Since it looks like you're not using Maven, you will need to download the implementation JAR from Maven Central manually: https://repo1.maven.org/maven2/org/glassfish/javax.json/1.1/

由于看起来您没有使用 Maven，因此您需要手动从 Maven Central 下载实现 JAR：https: //repo1.maven.org/maven2/org/glassfish/javax.json/1.1/

Or just click this direct link to download the JAR: javax.json-1.1.jar

或者只需单击此直接链接即可下载 JAR：javax.json-1.1.jar