Python PyQt:如何连接 QComboBox 以使用参数运行

声明:本页面是StackOverFlow热门问题的中英对照翻译,遵循CC BY-SA 4.0协议,如果您需要使用它,必须同样遵循CC BY-SA许可,注明原文地址和作者信息,同时你必须将它归于原作者(不是我):StackOverFlow 原文地址: http://stackoverflow.com/questions/23116763/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me): StackOverFlow

提示:将鼠标放在中文语句上可以显示对应的英文。显示中英文
时间:2020-08-19 02:17:33  来源:igfitidea点击:

PyQt: How to connect QComboBox to function with Arguments

pythonpyqt

提问by alphanumeric

QComboBox is connected to a function using following syntax:

QComboBox 使用以下语法连接到函数:

myComboBox.activated.connect(self.myFunction )

But I need to be able to send the arguments from ComboBox to myFunction(). But if I use:

但我需要能够将参数从 ComboBox 发送到 myFunction()。但如果我使用:

myComboBox.activated.connect(self.myFunction(myArg1, myArg2 )

I am getting

我正进入(状态

TypeError: connect() slot argument should be a callable or a signal, not 'NoneType'

What syntax needs to be used to connect a QComboBox to a function that is able to receive arguments sent from Comobobox?

需要使用什么语法将 QComboBox 连接到能够接收从 Comobobox 发送的参数的函数?

EDITED LATER:

稍后编辑:

Here is the code resulting an TypeError:

这是导致 TypeError 的代码:

connect() slot argument should be a callable or a signal, not 'NoneType'

connect() slot argument should be a callable or a signal, not 'NoneType'



from PyQt4 import QtCore, QtGui
import sys

class MyClass(object):
    def __init__(self, arg):
        super(MyClass, self).__init__()
        self.arg = arg        

class myWindow(QtGui.QWidget):
    def __init__(self, parent=None):
        super(myWindow, self).__init__(parent)

        self.comboBox = QtGui.QComboBox(self)
        self.comboBox.addItems([str(x) for x in range(3)])

        self.myObject=MyClass(id(self) )

        self.comboBox.activated.connect(self.myFunction(self.myObject, 'someArg'))

    def myFunction(self, arg1=None, arg2=None):
        print '\n\t myFunction(): ', type(arg1),type(arg2)

if __name__ == "__main__":
    app = QtGui.QApplication(sys.argv)
    app.setApplicationName('myApp')
    dialog = myWindow()
    dialog.show()
    sys.exit(app.exec_())

采纳答案by alphanumeric

After I posted a question Stachoverflow suggested a link which explained a lot. Here is the answer:

在我发布了一个问题之后,Stachoverflow 建议了一个链接,该链接解释了很多。答案如下:

from PyQt4 import QtCore, QtGui

class MyClass(object):
    def __init__(self, arg):
        super(MyClass, self).__init__()
        self.arg = arg        

class myWindow(QtGui.QWidget):
    def __init__(self, parent=None):
        super(myWindow, self).__init__(parent)

        self.comboBox = QtGui.QComboBox(self)
        self.comboBox.addItems([str(x) for x in range(3)])

        self.myObject=MyClass(id(self) )

        slotLambda = lambda: self.indexChanged_lambda(self.myObject)
        self.comboBox.currentIndexChanged.connect(slotLambda)

    @QtCore.pyqtSlot(str)
    def indexChanged_lambda(self, string):
        print 'lambda:', type(string), string

if __name__ == "__main__":
    app = QtGui.QApplication(sys.argv)
    app.setApplicationName('myApp')
    dialog = myWindow()
    dialog.show()
    sys.exit(app.exec_())