javascript 在javascript正则表达式中选择任何符号
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Choose any symbol in javascript regex
提问by Olga
I have a string containing something like this
我有一个包含类似内容的字符串
"... /\*start anythingCanBeEnteredHere end\*/ ..."
I need a regex that gets only the anythingCanBeEnteredHerepart, which can be a collection of any number of symbols.
我需要一个只获取anythingCanBeEnteredHere部分的正则表达式，它可以是任意数量符号的集合。
The problem is that I can't find any shortcut/flag that will choose any symbol
问题是我找不到任何可以选择任何符号的快捷方式/标志
So far I use this regex
到目前为止，我使用这个正则表达式
var regex = /start([^\~]*)end/;
var templateCode = myString.match(regex);
[^\~]chooses any symbol except "~"(which is a hack) and works fine, but I really need all symbols.
[^\~]选择除"~"（这是一个黑客）之外的任何符号并且工作正常，但我真的需要所有符号。
I've also tried this [^]but it doesn't work right.
我也试过这个，[^]但它不起作用。
回答by georg
/start(.*)end/
will match FOOin startFOOendand BARendBAZin startBARendBAZend.
将匹配FOOinstartFOOend和BARendBAZin startBARendBAZend。
/start(.*?)end/
will match FOOin startFOOendand BARin startBARendBAZend.
将匹配FOOinstartFOOend和BARin startBARendBAZend。
The dot matches anything except a newline symbol (\n). If you want to capture newlines as well, replace dot with [\s\S]. Also, if you don't allow the match to be empty (as in startend), use +instead of *.
点匹配除换行符 ( \n)之外的任何内容。如果您还想捕获换行符，请将 dot 替换为[\s\S]. 此外，如果您不允许匹配为空（如startend），请使用+代替*。
See http://www.regular-expressions.info/reference.htmlfor more info.
有关更多信息，请参阅http://www.regular-expressions.info/reference.html。
回答by Sam Greenhalgh
I'm not sure I understand what you mean by "symbol", if you mean anything, that's what the dot .will match
我不确定我是否理解你所说的“符号”是什么意思，如果你有什么意思，那就是点.匹配的意思
Are you trying to do this?
你想这样做吗？
var regex = /start(.*)end/;
var templateCode = myString.match(regex);
