Bash：查找具有最大行数的文件
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Bash: Find file with max lines count
提问by Marek Sebera
This is my try to do it
这是我的尝试
- Find all
*.javafilesfind . -name '*.java' - Count lines
wc -l - Delete last line
sed '$d' - Use AWK to find max lines-count in
wcoutputawk 'max=="" || data=="" || $1 > max {max=$1 ; data=$2} END{ print max " " data}'
- 查找所有
*.java文件find . -name '*.java' - 计数线
wc -l - 删除最后一行
sed '$d' - 使用 AWK 在
wc输出中查找最大行数awk 'max=="" || data=="" || $1 > max {max=$1 ; data=$2} END{ print max " " data}'
then merge it to single line
然后将其合并为单行
find . -name '*.java' | xargs wc -l | sed '$d' | awk 'max=="" || data=="" || > max {max= ; data=} END{ print max " " data}'
Can I somehow implement counting just non-blank lines?
我可以以某种方式实现只计算非空行吗？
回答by Shawn Chin
find . -type f -name "*.java" -exec grep -H -c '[^[:space:]]' {} \; | \
sort -nr -t":" -k2 | awk -F: '{print ; exit;}'
Replace the awkcommand with head -n1if you also want to see the number of non-blank lines.
如果您还想查看非空白行的数量，请将awk命令替换为head -n1。
Breakdown of the command:
命令分解：
find . -type f -name "*.java" -exec grep -H -c '[^[:space:]]' {} \;
'---------------------------' '-----------------------'
| |
for each *.java file Use grep to count non-empty lines
-H includes filenames in the output
(output = ./full/path/to/file.java:count)
| sort -nr -t":" -k2 | awk -F: '{print ; exit;}'
'----------------' '-------------------------'
| |
Sort the output in Print filename of the first entry (largest count)
reverse order using the then exit immediately
second column (count)
回答by Vijay
find . -name "*.java" -type f | xargs wc -l | sort -rn | grep -v ' total$' | head -1
回答by holygeek
Something like this might work:
像这样的事情可能会奏效：
find . -name '*.java'|while read filename; do
nlines=`grep -v -E '^[[:space:]]*$' "$filename"|wc -l`
echo $nlines $filename
done|sort -nr|head -1
(edited as per Ed Morton's comment. I must have had too much coffee :-) )
（根据 Ed Morton 的评论进行编辑。我一定是喝了太多咖啡 :-) ）
回答by Ed Morton
To get the size of all of your files using awk is just:
要使用 awk 获取所有文件的大小，只需：
$ find . -name '*.java' -print0 | xargs -0 awk '
BEGIN { for (i=1;i<ARGC;i++) size[ARGV[i]]=0 }
{ size[FILENAME]++ }
END { for (file in size) print size[file], file }
'
To get the count of the non-empty lines, simply make the line where you increment the size[] conditional:
要获得非空行的计数，只需将增加 size[] 的行设置为有条件的：
$ find . -name '*.java' -print0 | xargs -0 awk '
BEGIN { for (i=1;i<ARGC;i++) size[ARGV[i]]=0 }
NF { size[FILENAME]++ }
END { for (file in size) print size[file], file }
'
(If you want to consider lines that contain only blanks as "empty" then replace NF with /^./.)
（如果您想将仅包含空格的行视为“空”，则将 NF 替换为 /^./。）
To get only the file with the most non-empty lines just tweak again:
要仅获取具有最多非空行的文件，只需再次调整：
$ find . -name '*.java' -print0 | xargs -0 awk '
BEGIN { for (i=1;i<ARGC;i++) size[ARGV[i]]=0 }
NF { size[FILENAME]++ }
END {
for (file in size) {
if (size[file] >= maxSize) {
maxSize = size[file]
maxFile = file
}
}
print maxSize, maxFile
}
'
