mongodb 如何在mongoosejs中findAll？
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How to findAll in mongoosejs?
提问by murvinlai
My code is like that:
我的代码是这样的：
SiteModel.find(
{},
function(docs) {
next(null, { data: docs });
}
);
but it never returns anything... but if I specify something in the {} then there is one record. so, how to findall?
但它从不返回任何内容……但如果我在 {} 中指定了某些内容，则只有一条记录。那么，如何findall？
回答by pepo
Try this code to debug:
试试这个代码来调试：
SiteModel.find({}, function(err, docs) {
if (!err) {
console.log(docs);
process.exit();
}
else {
throw err;
}
});
回答by Tim Knipe
The 2017 Node 8.5 way
2017 Node 8.5 方式
try {
const results = await SiteModel.find({});
console.log(results);
} catch (err) {
throw err;
}
回答by Deeksha Sharma
From the documentation:
从文档：
let result = SiteModel.find({}, function (err, docs) {});
or using async await you can do like this also:
或者使用 async await 你也可以这样做：
let result = await SiteModel.find({});
回答by Ogala
const result = await SiteModel.find()- Without the {}in the .find()function works as well.
const result = await SiteModel.find()- 没有{}in.find()函数也能工作。
