ErrorException: 未定义的变量 laravel
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ErrorException: Undefined variable laravel
提问by Pain
I'm trying to pass variables from controller to view i tried both compact and with but nothing works, i get this error:
我正在尝试从控制器传递变量以查看我尝试了紧凑和有但没有任何效果，我收到此错误：
ErrorException undefined variable: programs.
ErrorException 未定义变量：程序。
Controller
控制器
public function getManageCourse(){
$programs = Program::all();
$academics = Academic::orderBy('academic_id','DESC')->get();
return view(('courses.manageCourse'),compact('programs','academics'));
}
View
看法
<div class="col-sm-4">
<label for="program">Course</label>
<div class="input-group">
<select class="form-control" name="program_id" id="program_id">
<option value="">------------</option>
@foreach($programs as $key =>$p)
<option value="{{$p->$program_id}}">{{$y->program}}</option>
@endforeach
</select>
<div class="input-group-addon">
<span class="fa fa-plus" id="add-more-program"></span>
</div>
</div>
</div>
I have looked into similar problems but i didn't find a solution, why is this happening? what am i doing wrong?
我已经研究过类似的问题，但我没有找到解决方案，为什么会发生这种情况？我究竟做错了什么？
回答by Leo
make it like this:
让它像这样：
return view('courses.manageCourse',compact('programs','academics'));
not like you are doing it:
不像你这样做：
return view(('courses.manageCourse'),compact('programs','academics'));
回答by Pain
I found the solution i was doing $p->$program_idinstead of $p->program_id
我找到了我正在做的解决方案$p->$program_id而不是$p->program_id
回答by Shery
write
写
return view('courses.manageCourse',compact('programs','academics'));
and
和
<option value="{{$p->$program_id}}">{{$p->program}}</option>
instead of
代替
<option value="{{$p->$program_id}}">{{$y->program}}</option>
