C++ 循环询问用户输入数组
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Loop asking user for input into an array
提问by audiedoggie
You all have helped me so much in the past, I am coming back for more help!
过去你们都帮了我很多，我会回来寻求更多帮助！
I am working on another C++ assignment for school. I have to collect 20 numbers between 10 and 100 from the user and compare them all and print out the ones that are not duplicates.
我正在为学校做另一项 C++ 作业。我必须从用户那里收集 10 到 100 之间的 20 个数字并将它们全部进行比较并打印出不重复的数字。
The part I am stuck on is trying to get the user input to loop until I have all 20 numbers. What I have makes sense to me, but it apparently is not working. Sorry for the ridiculous comments, I have to comment everything for class.
我坚持的部分是试图让用户输入循环，直到我拥有所有 20 个数字。我所拥有的对我来说很有意义，但它显然不起作用。对不起，这些荒谬的评论，我必须为课堂评论所有内容。
Any light you can shed on my goof up would be amazing! Thank you so much!
你能在我的愚蠢行为上散发出的任何光芒都会很棒！非常感谢！
int FindDuplicates[20]; // my little array
int UserInput; // the number from the user to compare
int count; // the number of numbers entered
for(count=0; count<FindDuplicates; count++;) // what I am trying to do is have count start at 0. as long as it is less than the max array, add 1 to the count
{
cout << "Please enter a number between 10 and 100: "; // print out what I would like
cin >> UserInput; // get the number from the user
}
回答by ssell
for( int count = 0; count < 20; count++ )
{
cout << "Please enter a number between 10 and 100: ";
cin >> userInput;
FindDuplicates[ count ] = userInput;
}
You can also check for valid input with:
您还可以通过以下方式检查有效输入：
while( UserInput < 10 || UserInput > 100 )
{
cout << "Please enter a number between 10 and 100: ";
cin >> UserInput;
}
If you do that just make sure you have initialized UserInput to something. So:
如果您这样做，请确保您已将 UserInput 初始化为某些内容。所以：
int FindDuplicates[ 20 ];
int UserInput = 0;
int count = 0;
//count has already been defined, so no need to do it again
for( ; count < 20; count++ )
{
//Keep asking until valid input is given
while( UserInput < 10 || UserInput > 100 )
{
cout << "Please enter a number between 10 and 100: ";
cin >> userInput;
}
//Add userInput into the array
FindDuplicates[ count ] = UserInput;
}
回答by michael.shan
your problem is how to enter 20 valid numbers, is it? I think the do while loop will help you.
你的问题是如何输入20个有效数字，是吗？我认为 do while 循环会帮助你。
int FindDuplicates[20]; // my little array
int UserInput; // the number from the user to compare
int count = 0; // the number of numbers entered
do
{
cout << "Please enter a number between 10 and 100: "; // print out what I would like
cin >> UserInput; // get the number from the user
if (UserInput >= 10 && UserInput <= 100)
count++;
} while (count < 20);
Hope that will help you.
希望这会帮助你。
回答by zw324
回答by Richard
There is a syntax error on the line below, check how for statements work. There's also a problem with the <FindDuplicates. Make sure you understand what that variable means.
下面一行有语法错误，请检查 for 语句是如何工作的。也有问题<FindDuplicates。确保您了解该变量的含义。
for(count=0; count<FindDuplicates; count++;)
for(count=0; count<FindDuplicates; count++;)
