pandas 如何在 Seaborn 点图上获取数据标签？
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How to get data labels on a Seaborn pointplot?
提问by lostsoul29
I have two arrays like so:
我有两个这样的数组：
Soldier_years = [1850, 1851, 1852, 1853, 1854, 1855, 1856, 1857, 1858, 1859, 1860, 1861, 1862, 1863, 1864, 1865, 1866, 1867, 1868, 1869, 1870]
num_records_yob = [7, 5, 8, 9, 15, 17, 23, 19, 52, 55, 73, 73, 107, 137, 65, 182, 228, 257, 477, 853, 2303]
I'm trying to get these into a Seaborn pointplot like so:
我正在尝试将这些放入 Seaborn 点图，如下所示：
%matplotlib inline
import seaborn as sns
import matplotlib.pyplot as plt
sns.set(style="darkgrid")
f, (ax) = plt.subplots(figsize=(12, 6), sharex=True)
sns.set_style("darkgrid")
ax = sns.pointplot(x=Soldier_years, y=num_records_yob)
I get a pointplot like so:
我得到一个像这样的点图：
This plot is almost what I want. How do I get the data labels of each of the points to show above the respective points?
这个情节几乎是我想要的。如何获取每个点的数据标签以显示在相应点上方？
I tried ax.patches, but it is empty.
我试过ax.patches，但它是空的。
I'm trying to get it look like this (but for the pointplot):
我试图让它看起来像这样（但对于点图）：
回答by MaxU
you can do it this way:
你可以这样做：
[ax.text(p[0], p[1]+50, p[1], color='g') for p in zip(ax.get_xticks(), num_records_yob)]
回答by borgr
For future reference that will want a more general answer I suggest this code:
为了将来需要更一般答案的参考，我建议使用以下代码：
ymin, ymax = ax.get_ylim()
color="#3498db" # choose a color
bonus = (ymax - ymin) / 50 # still hard coded bonus but scales with the data
for x, y, name in zip(X, Y, names):
ax.text(x, y + bonus, name, color=color)
Note that I also changed the comprehension to a for loop, I think it is more readable that way (when the list is actually thrown away)
请注意，我还将理解更改为 for 循环，我认为这样更具可读性（当列表实际上被丢弃时）
