java 如何获取任何应用程序上下文根的文件系统路径
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How to get file system path of the context root of any application
提问by Pedantic
I am working on web application.I invoke on my jsp request.getContextPath(), but strangely I got address /streetshop.
我正在开发网络应用程序。我在我的 jsp 上调用request.getContextPath()，但奇怪的是我得到了地址/streetshop。
Then I am appending some path as request.getContextPath() + "abc"and create folder.
然后我附加一些路径request.getContextPath() + "abc"并创建文件夹。
Then its creating folder in D://instead of my webapplication folder.
然后它的创建文件夹D://而不是我的 webapplication 文件夹。
Please, tell me, I want to upload an image in put it in my web-application root/images/images.gif.
请告诉我，我想上传一张图片并将其放入我的web-application root/images/images.gif.
回答by home
You mix things up here. HttpServletRequest.getContextPath()returns your web application root path. In your example this is /streetshop, so your URL may look similar to www.myapp.com/streetshop. If you want to access the internal file system path, you must obtain it from the ServletContextusing request.getServletContext().getRealPath("/"). This should return the location of your WAR files' WebContentfolder.
你在这里搞混了。HttpServletRequest.getContextPath()返回您的 Web 应用程序根路径。在您的示例中，这是/streetshop，因此您的 URL 可能类似于www.myapp.com/streetshop. 如果要访问内部文件系统路径，必须从ServletContextusing 中获取request.getServletContext().getRealPath("/")。这应该返回 WAR 文件文件WebContent夹的位置。
Keep in mind that if you modify contents of this path during runtime, you're going to loose everything when redeploying your application.
请记住，如果您在运行时修改此路径的内容，您将在重新部署应用程序时丢失所有内容。
