java 将包含二进制值的字符串转换为十六进制
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Translating a String containing a binary value to Hex
提问by Yuri
I am trying to translate a String that contains a binary value (e.g. 000010001010011) to it's Hex value.(453)
我正在尝试将包含二进制值（例如 000010001010011）的字符串转换为它的十六进制值。（453）
I've been trying several options, but mostly I get a converted value of each individual character. (0=30 1=31)
我一直在尝试几种选择，但大多数情况下我都会得到每个字符的转换值。(0=30 1=31)
I have a function that translates my input to binary code through a non-mathematical way, but through a series of "if, else if" statements. (the values are not calculated, because they are not standard.) The binary code is contained in a variable String "binOutput"
我有一个函数可以通过非数学方式将我的输入转换为二进制代码，但是通过一系列“if, else if”语句。（这些值不是计算出来的，因为它们不是标准的。）二进制代码包含在变量字符串“binOutput”中
I currently have something like this:
我目前有这样的事情：
String bin = Integer.toHexString(Integer.parseInt(binOutput));
But this does not work at all.
但这根本行不通。
回答by Ted Hopp
Try using Integer.parseInt(binOutput, 2)instead of Integer.parseInt(binOutput)
尝试使用Integer.parseInt(binOutput, 2)代替Integer.parseInt(binOutput)
回答by jcomeau_ictx
Ted Hopp beat me to it, but here goes anyway:
泰德霍普打败了我，但无论如何：
jcomeau@intrepid:/tmp$ cat test.java; java test 000010001010011
public class test {
public static void main(String[] args) {
for (int i = 0; i < args.length; i++) {
System.out.println("The value of " + args[i] + " is " +
Integer.toHexString(Integer.parseInt(args[i], 2)));
}
}
}
The value of 000010001010011 is 453
