如何在 Python 中使用基数为 5 的数字？
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How can I work with base 5 numbers in Python?
提问by Pepijn
Possible Duplicate:
convert integer to a string in a given numeric base in python
可能的重复：
在python中将整数转换为给定数字基数的字符串
I want to work with base 5 numbers, or any other non standard base for that matter.
我想使用基数为 5 的数字，或任何其他非标准基数。
I found out int('123', 5)works, but I need to go the other way around.
我发现了int('123', 5)作品，但我需要反过来。
Should I write my own number class to accomplish this?
我应该编写自己的数字类来完成这个吗？
Maybe I'm just thinking in the wrong direction...
也许我只是想错了方向......
采纳答案by John La Rooy
def to_base_5(n):
s = ""
while n:
s = str(n % 5) + s
n /= 5
return s
回答by Shane Holloway
I had fun with this a while ago for a python-dev thread. The original post can be found at http://mail.python.org/pipermail/python-dev/2006-January/059925.htmlThis particular algorithm can perform floating point bases as well.
不久前，我在一个 python-dev 线程中玩得很开心。原始帖子可以在http://mail.python.org/pipermail/python-dev/2006-January/059925.html找到。 这个特定的算法也可以执行浮点运算。
#!/usr/bin/env python
import math
def ibase(n, radix=2, maxlen=None):
r = []
while n:
n,p = divmod(n, radix)
r.append('%d' % p)
if maxlen and len(r) > maxlen:
break
r.reverse()
return ''.join(r)
def fbase(n, radix=2, maxlen=8):
r = []
f = math.modf(n)[0]
while f:
f, p = math.modf(f*radix)
r.append('%.0f' % p)
if maxlen and len(r) > maxlen:
break
return ''.join(r)
def base(n, radix, maxfloat=8):
if isinstance(n, float):
return ibase(n, radix)+'.'+fbase(n, radix, maxfloat)
elif isinstance(n, (str, unicode)):
n,f = n.split('.')
n = int(n, radix)
f = int(f, radix)/float(radix**len(f))
return n + f
else:
return ibase(n, radix)
if __name__=='__main__':
pi = 3.14
print 'pi:', pi, 'base 10'
piBase3 = base(pi, 3)
print 'pi:', piBase3, 'base 3'
piFromBase3 = base(piBase3, 3)
print 'pi:', piFromBase3, 'base 10 from base 3'
