java 在 JPA-QL 查询中加入集合

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时间:2020-10-30 17:13:40  来源:igfitidea点击:

Joining to a collection in a JPA-QL query

javajpa

提问by rym

I'am using JPA for mapping ,I have this entity Class

我正在使用 JPA 进行映射,我有这个实体类

@Entity
@Table(name = "h_pe")
@XmlRootElement
@NamedQueries({

public class HPe implements Serializable {
 private static final long serialVersionUID = 1L;
 @EmbeddedId
 protected HPePK hPePK;
 @Column(name = "PE_TIMEOUT")
 private Integer peTimeout;
 @Column(name = "PE_STATUS")
 private Boolean peStatus;
 @OneToMany(cascade = CascadeType.ALL, mappedBy = "hPe")
 private Collection<HPesp> hPespCollection;
 @JoinColumn(name = "PE_ENV", referencedColumnName = "ENV_URL", insertable = false, updatable = false)
 @ManyToOne(optional = false)
 private HEnv hEnv;
 @JoinColumn(name = "PE_PLATFORM", referencedColumnName = "PLATFORM_NAME", insertable = false, updatable = false)
 @ManyToOne(optional = false)
 private HPlatform hPlatform;

}

I want to write a request JPA like the following(I have wrote it with SQl ),I have tried to write it but I haven't understood how to use PE_ENV because it is the result of OneToMany relationship!

我想写一个像下面这样的请求JPA(我已经用SQl写了它),我已经尝试写了但我不明白如何使用PE_ENV,因为它是OneToMany关系的结果!

select distinct h_env.env_name,h_platform.PLATFORM_NAME
from h_env,h_platform,h_pe
where h_env.ENV_URL=h_pe.PE_ENV
and h_platform.PLATFORM_NAME=h_pe.PE_PLATFORM
and h_platform.PLATFORM_NAME='XXX';

回答by James

Select e.name, p.name
from HPe hp join hp.hPlatform p join hp.hPespCollection p
where p.name = 'xxx'

See, http://en.wikibooks.org/wiki/Java_Persistence/Querying#Common_Queries

见, http://en.wikibooks.org/wiki/Java_Persistence/Querying#Common_Queries