Python 从seaborn保存情节
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Saving plot from seaborn
提问by Roxana Noelia
When I try to save my plot working with seaborn, like this:
当我尝试使用 seaborn 保存我的情节时，如下所示：
import seaborn as sn
import pandas as pd
import matplotlib.pyplot as plt
from pylab import savefig
array = [[100,0],
[33,67]]
df_cm = pd.DataFrame(array)
svm = sn.heatmap(df_cm, annot=True,cmap='coolwarm', linecolor='white', linewidths=1)
svm.savefig('svm_conf.png', dpi=400)
I get this error
我收到这个错误
AttributeError Traceback (most recent call last)
<ipython-input-71-5c0ae9cda020> in <module>()
----> 1 svm.savefig('svm_conf.png', dpi=400)
AttributeError: 'AxesSubplot' object has no attribute 'savefig'
I have saved some boxplots before, with the same code, but this time, it doesn't work.
我之前用相同的代码保存了一些箱线图，但是这一次，它不起作用。
回答by Adonis
Actually what you would need to do is:
其实你需要做的是：
- Retrieve the figure from the object returned by
sn.heatmap - Then and only then save the figure
- 从返回的对象中检索图形
sn.heatmap - 然后才保存图
See the last 2 lines below:
请参阅下面的最后两行：
import seaborn as sn
import pandas as pd
import matplotlib.pyplot as plt
from pylab import savefig
array = [[100,0],
[33,67]]
df_cm = pd.DataFrame(array)
svm = sn.heatmap(df_cm, annot=True,cmap='coolwarm', linecolor='white', linewidths=1)
figure = svm.get_figure()
figure.savefig('svm_conf.png', dpi=400)
回答by ImportanceOfBeingErnest
The command to save the current figure would be
保存当前图形的命令是
plt.savefig()
Because that apparently causes some confusion, here is the full working example:
因为这显然会引起一些混乱，这里是完整的工作示例：
import seaborn as sn
import pandas as pd
import matplotlib.pyplot as plt
array = [[100,0],
[33,67]]
df_cm = pd.DataFrame(array)
svm = sn.heatmap(df_cm, annot=True,cmap='coolwarm', linecolor='white', linewidths=1)
plt.savefig('svm_conf.png', dpi=400)
回答by MosteM
The easiest way would be to use
最简单的方法是使用
plt.savefig('svm_conf.png', dpi=400)
instead of
代替
svm.savefig('svm_conf.png', dpi=400)
