在教程中，我们将查看一个shell脚本，可以快速找到Linux服务器中最大的目录。
如果要在文件系统上清理空间，这非常有用。

shell脚本显示X在给定目录路径中消耗空间的目录数。
在我使用du命令的脚本中，然后排序和头命令。

脚本找到最大的目录

让如何编写脚本以查找顶端目录，如下所示：

#/bin/bash
#check if user input argument
if [ $# -eq 0 ]; then
#if no argument print next messge and exit from script
echo "Usage: 
./top5dir.sh /home/yevhen/
Here is the biggest directories located in /home/yevhen/:
N°1 : /home/yevhen//Fly is 14043 Mb
N°2 : /home/yevhen//VirtualBox VMs is 5837 Mb
N°3 : /home/yevhen//Downloads is 2224 Mb
N°4 : /home/yevhen//.icedove is 963 Mb
N°5 : /home/yevhen//Downloads is 645 Mb
N°6 : /home/yevhen//.wine is 602 Mb
N°7 : /home/yevhen//.cache is 324 Mb
N°8 : /home/yevhen//Dropbox is 324 Mb
N°9 : /home/yevhen//.config is 263 Mb
N°10 : /home/yevhen//.local is 153 Mb
 "
exit 1
fi
# Save first arguments to variables
CheckedDir=""
#HeadValue=
#set value for variable count value 1
count=1
#just print empty line
echo ""
#Print next message:
echo "Here is the ${HeadValue} biggest directories located in ${CheckedDir}:"
echo ""
#Getting list of directories and space they use.
du -a --max-depth=1 --one-file-system ${CheckedDir}/|
#next we sort result
sort -rn |
sed "1d" |
# next we get only first X directories
head -"${HeadValue}" |
#next print result to user
while read size dirrr ; do
#counting size in Mb
size="$(( size/1024 ))"
#show output for user
echo "N°${count} : ${dirrr} is ${size} Mb"
((count++))
done
echo ""

脚本输出