Java 如何使用 get() 方法访问 arrayList 中的元素？
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How would use a get() method to access an element in an arrayList?
提问by user1254044
This is my code I have so far but I don't know how to access an element in the Array myList?
这是我到目前为止的代码，但我不知道如何访问数组 myList 中的元素？
And is the inex of an array list start at 0 or 1? I have just found out about array lists and i need a few pointers and some help
数组列表的 inex 是从 0 还是 1 开始？我刚刚发现了数组列表，我需要一些指针和一些帮助
ArrayList<String> myList = new ArrayList<String>();
myList.add("hello");
myList.add("5");
myList.add("3");
myList.add("8");
int totalElements = myList.size();
System.out.println(totalElements);
private String[] myList;
public String getList() {
return this.myList[0];
回答by donnior
In java, array's index is start from 0.
在java中，数组的索引从0开始。
To access the nth element in one list, you can call list.get(n).
要访问一个列表中的第 n 个元素，您可以调用list.get(n).
回答by juergen d
String a = myList.get(0); //a = "hello"
String b = myList.get(1); //b = "5"
回答by noMAD
All you have to do is:
您所要做的就是：
myList.get(Index);
This would return you the type of Objectyou used while creating the ArrayList. In your case it will return a String. Hence, what you can do is:
这将返回您Object在创建ArrayList. 在您的情况下，它将返回一个String. 因此，您可以做的是：
String firstElement = myList.get(0); //This would return "Hello"
This also shows that ArrayListindices start with 0
这也表明ArrayList索引从 0 开始
