php PHP致命错误：定义函数时调用未定义的函数
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PHP Fatal error: Call to undefined function when function is defined
提问by Ben Alter
I am getting an error in PHP:
我在 PHP 中遇到错误：
PHP Fatal error: Call to undefined function getCookie
Code:
代码：
include('Core/dAmnPHP.php');
$tokenarray = getCookie($username, $password);
Inside of dAmnPHP.php, it includes a function called getCookie inside class dAmnPHP. When I run my script it tells me that the function is undefined.
在 dAmnPHP.php 中，它在类 dAmnPHP 中包含一个名为 getCookie 的函数。当我运行脚本时，它告诉我该函数未定义。
What am I doing wrong?
我究竟做错了什么？
回答by Maythe
It looks like you need to create a new instance of the class before you can use its functions.
看起来您需要先创建该类的新实例，然后才能使用其功能。
Try:
$dAmn = new dAmnPHP;
$dAmn->getCookie($username, $password);
尝试：
$dAmn = new dAmnPHP;
$dAmn->getCookie($username, $password);
I've not used dAmn before, so I can't be sure, but I pulled my info from here: https://github.com/DeathShadow/Contra/blob/master/core/dAmnPHP.php
我以前没有使用过 dAmn，所以我不能确定，但我从这里提取了我的信息：https: //github.com/DeathShadow/Contra/blob/master/core/dAmnPHP.php
回答by Eric Leschinski
How to reproduce this error:
如何重现此错误：
Put this in a file called a.php:
把它放在一个名为 a.php 的文件中：
<?php
include('b.php');
umad();
?>
Put this in a file called b.php:
把它放在一个名为 b.php 的文件中：
<?php
class myclass{
function umad(){
print "ok";
}
}
?>
Run it:
运行：
PHP Fatal error: Call to undefined function umad() in
/home/el/a.php on line 4
What went wrong:
什么地方出了错：
You can't use methods inside classes without instantiating them first. Do it like this:
你不能在类中使用方法而不先实例化它们。像这样做：
<?php
include('b.php');
$mad = new myclass;
$mad->umad();
?>
Then the php interpreter can find the method:
然后php解释器就可以找到方法了：
eric@dev ~ $ php a.php
ok
