Linux 我如何回忆上一个 bash 命令的参数？
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How can I recall the argument of the previous bash command?
提问by The Coder
Is there a way in Bash to recall the argument of the previous command?
Bash 有没有办法回忆上一个命令的参数？
I usually do vi file.cfollowed by gcc file.c.
我通常这样做，vi file.c其次是gcc file.c.
Is there a way in Bash to recall the argument of the previous command?
Bash 有没有办法回忆上一个命令的参数？
采纳答案by codaddict
You can use $_or !$to recall the last argument of the previous command.
您可以使用$_或!$来调用上一个命令的最后一个参数。
Also Alt + .can be used to recall the last argument of any of the previous commands.
也Alt + .可用于调用任何先前命令的最后一个参数。
回答by Justin Ethier
Yes, you can use !$to recall the last argument of the preceding command.
是的，您可以使用!$来调用前面命令的最后一个参数。
回答by Robert Gowland
If the previous command had two arguments, like this
如果前面的命令有两个参数，像这样
ls a.txt b.txt
and you wanted the first one, you could type
你想要第一个，你可以输入
!:1
giving
给予
a.txt
Or if you wanted both, you could type
或者，如果你同时想要，你可以输入
!:1-2
giving
给予
a.txt b.txt
You can extend this to any number of arguments, eg:
您可以将其扩展到任意数量的参数，例如：
!:10-12
回答by Antonio Mano
In the command line you can press esc-.or alt+.
在命令行中，您可以按esc-.或alt+.
It cycles through the last argumentof your previous commands.
它循环遍历您之前命令的最后一个参数。
回答by Madisz
If you know the number given in the history for a particular command, you can pretty much take any argument in that command using following terms.
如果您知道特定命令的历史记录中给出的数字，您几乎可以使用以下术语在该命令中获取任何参数。
Use following to take the second argument from the third command in the history,
使用以下命令从历史记录中的第三个命令中获取第二个参数，
!3:2
!3:2
Use following to take the third argument from the fifth last command in the history,
使用以下命令从历史记录中的倒数第五个命令中获取第三个参数，
!-5:3
!-5:3
Using a minus sign, you ask it to traverse from the last command of the history.
使用减号，您要求它从历史记录的最后一个命令开始遍历。
回答by Johntron
!!:nwhere nis the 0-based position of the argument you want.
!!:nn您想要的参数的从 0 开始的位置在哪里。
For example:
例如：
echo 'one' 'two'
# "one two"
echo !!:2
# "two"
The !prefix is used to access previous commands.
该!前缀用于先前访问命令。
Other useful commands:
其他有用的命令：
!$- last argument from previous command!^- first argument (after the program/built-in/script) from previous command!!- previous command (often pronounced "bang bang")!n- command numbernfromhistory!pattern- most recent command matchingpattern!!:s/find/replace- last command, substitutefindwithreplace
!$- 上一个命令的最后一个参数!^- 上一个命令的第一个参数（在程序/内置/脚本之后）!!- 上一个命令（通常发音为“bang bang”）!n- 命令编号n来自history!pattern- 最近的命令匹配pattern!!:s/find/replace- 最后一个命令，替换find为replace
回答by Johntron
!* runs a new command with all previous arguments.
!* 运行带有所有先前参数的新命令。
ls /tmp
cd !*
#you are now in /tmp
