Javascript 如何在jquery ajax成功回调函数中传递上下文
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How to pass context in jquery ajax success callback function
提问by rajakvk
var Box = function(){
this.parm = {name:"rajakvk",year:2010};
Box.prototype.jspCall = function() {
$.ajax({
type: "post",
url: "some url",
success: this.exeSuccess,
error: this.exeError,
complete: this.exeComplete
});
}
this.exeSuccess = function(){
alert(this.parm.name);
}
}
I'm not getting Box object inside exeSuccess method. How to pass Box object inside exeSuccess method?
我没有在 exeSuccess 方法中获取 Box 对象。如何在 exeSuccess 方法中传递 Box 对象？
回答by Nick Craver
Use the contextoption, like this:
使用context选项，像这样：
$.ajax({
context: this,
type: "post",
url: "some url",
success: this.exeSuccess,
error: this.exeError,
complete: this.exeComplete
});
The context option determines what context the callback is called with...so it determines what thisrefers to inside that function.
上下文选项决定了调用回调的上下文......因此它决定了this该函数内部引用的内容。
