.NET NewtonSoft JSON 反序列化映射到不同的属性名称

.NET NewtonSoft JSON deserialize map to a different property name

提问by JenonD

I have following JSON string which is received from an external party.

我有以下来自外部方的 JSON 字符串。

{
   "team":[
      {
         "v1":"",
         "attributes":{
            "eighty_min_score":"",
            "home_or_away":"home",
            "score":"22",
            "team_id":"500"
         }
      },
      {
         "v1":"",
         "attributes":{
            "eighty_min_score":"",
            "home_or_away":"away",
            "score":"30",
            "team_id":"600"
         }
      }
   ]
}

My mapping classes:

我的映射类：

public class Attributes
{
    public string eighty_min_score { get; set; }
    public string home_or_away { get; set; }
    public string score { get; set; }
    public string team_id { get; set; }
}

public class Team
{
    public string v1 { get; set; }
    public Attributes attributes { get; set; }
}

public class RootObject
{
    public List<Team> team { get; set; }
}

The question is that I don't like the Attributesclass nameand the attributesfield namesin the Teamclass. Instead, I want it to be named TeamScoreand also to remove _from the field names and give proper names.

现在的问题是，我不喜欢的Attributes类名和attributes字段名的Team类。相反，我希望它被命名，TeamScore并_从字段名称中删除并给出适当的名称。

JsonConvert.DeserializeObject<RootObject>(jsonText);

I can rename Attributesto TeamScore, but if I change the field name (attributesin the Teamclass), it won't deserialize properly and gives me null. How can I overcome this?

我可以重命名Attributes为TeamScore，但是如果我更改字段名称（attributes在Team类中），它将无法正确反序列化并为我提供null. 我怎样才能克服这个问题？

回答by outcoldman

Json.NEThas a JsonPropertyAttributewhich allows you to specify the name of a JSON property, so your code should be:

Json.NET有一个JsonPropertyAttribute允许您指定 JSON 属性的名称，因此您的代码应该是：

public class TeamScore
{
    [JsonProperty("eighty_min_score")]
    public string EightyMinScore { get; set; }
    [JsonProperty("home_or_away")]
    public string HomeOrAway { get; set; }
    [JsonProperty("score ")]
    public string Score { get; set; }
    [JsonProperty("team_id")]
    public string TeamId { get; set; }
}

public class Team
{
    public string v1 { get; set; }
    [JsonProperty("attributes")]
    public TeamScore TeamScores { get; set; }
}

public class RootObject
{
    public List<Team> Team { get; set; }
}

Documentation: Serialization Attributes

文档：序列化属性

回答by Hyman

If you'd like to use dynamic mapping, and don't want to clutter up your model with attributes, this approach worked for me

如果您想使用动态映射，并且不想用属性弄乱模型，那么这种方法对我有用

Usage:

用法：

var settings = new JsonSerializerSettings();
settings.DateFormatString = "YYYY-MM-DD";
settings.ContractResolver = new CustomContractResolver();
this.DataContext = JsonConvert.DeserializeObject<CountResponse>(jsonString, settings);

Logic:

逻辑：

public class CustomContractResolver : DefaultContractResolver
{
    private Dictionary<string, string> PropertyMappings { get; set; }

    public CustomContractResolver()
    {
        this.PropertyMappings = new Dictionary<string, string> 
        {
            {"Meta", "meta"},
            {"LastUpdated", "last_updated"},
            {"Disclaimer", "disclaimer"},
            {"License", "license"},
            {"CountResults", "results"},
            {"Term", "term"},
            {"Count", "count"},
        };
    }

    protected override string ResolvePropertyName(string propertyName)
    {
        string resolvedName = null;
        var resolved = this.PropertyMappings.TryGetValue(propertyName, out resolvedName);
        return (resolved) ? resolvedName : base.ResolvePropertyName(propertyName);
    }
}

回答by Rentering.com

Adding to Hymans solution. I need to Deserialize using the JsonProperty and Serialize while ignoring the JsonProperty (or vice versa). ReflectionHelper and Attribute Helper are just helper classes that get a list of properties or attributes for a property. I can include if anyone actually cares. Using the example below you can serialize the viewmodel and get "Amount" even though the JsonProperty is "RecurringPrice".

添加到 Hymans 解决方案。我需要在忽略 JsonProperty 的同时使用 JsonProperty 和 Serialize 进行反序列化（反之亦然）。ReflectionHelper 和 Attribute Helper 只是获取属性列表或属性的属性列表的辅助类。如果有人真正关心，我可以包括在内。使用下面的示例，您可以序列化视图模型并获得“金额”，即使 JsonProperty 是“RecurringPrice”。

    /// <summary>
    /// Ignore the Json Property attribute. This is usefule when you want to serialize or deserialize differently and not 
    /// let the JsonProperty control everything.
    /// </summary>
    /// <typeparam name="T"></typeparam>
    public class IgnoreJsonPropertyResolver<T> : DefaultContractResolver
    {
        private Dictionary<string, string> PropertyMappings { get; set; }

        public IgnoreJsonPropertyResolver()
        {
            this.PropertyMappings = new Dictionary<string, string>();
            var properties = ReflectionHelper<T>.GetGetProperties(false)();
            foreach (var propertyInfo in properties)
            {
                var jsonProperty = AttributeHelper.GetAttribute<JsonPropertyAttribute>(propertyInfo);
                if (jsonProperty != null)
                {
                    PropertyMappings.Add(jsonProperty.PropertyName, propertyInfo.Name);
                }
            }
        }

        protected override string ResolvePropertyName(string propertyName)
        {
            string resolvedName = null;
            var resolved = this.PropertyMappings.TryGetValue(propertyName, out resolvedName);
            return (resolved) ? resolvedName : base.ResolvePropertyName(propertyName);
        }
    }

Usage:

用法：

        var settings = new JsonSerializerSettings();
        settings.DateFormatString = "YYYY-MM-DD";
        settings.ContractResolver = new IgnoreJsonPropertyResolver<PlanViewModel>();
        var model = new PlanViewModel() {Amount = 100};
        var strModel = JsonConvert.SerializeObject(model,settings);

Model:

模型：

public class PlanViewModel
{

    /// <summary>
    ///     The customer is charged an amount over an interval for the subscription.
    /// </summary>
    [JsonProperty(PropertyName = "RecurringPrice")]
    public double Amount { get; set; }

    /// <summary>
    ///     Indicates the number of intervals between each billing. If interval=2, the customer would be billed every two
    ///     months or years depending on the value for interval_unit.
    /// </summary>
    public int Interval { get; set; } = 1;

    /// <summary>
    ///     Number of free trial days that can be granted when a customer is subscribed to this plan.
    /// </summary>
    public int TrialPeriod { get; set; } = 30;

    /// <summary>
    /// This indicates a one-time fee charged upfront while creating a subscription for this plan.
    /// </summary>
    [JsonProperty(PropertyName = "SetupFee")]
    public double SetupAmount { get; set; } = 0;


    /// <summary>
    /// String representing the type id, usually a lookup value, for the record.
    /// </summary>
    [JsonProperty(PropertyName = "TypeId")]
    public string Type { get; set; }

    /// <summary>
    /// Billing Frequency
    /// </summary>
    [JsonProperty(PropertyName = "BillingFrequency")]
    public string Period { get; set; }


    /// <summary>
    /// String representing the type id, usually a lookup value, for the record.
    /// </summary>
    [JsonProperty(PropertyName = "PlanUseType")]
    public string Purpose { get; set; }
}

回答by Shimmy Weitzhandler

Expanding Rentering.com'sanswer, in scenarios where a whole graph of many types is to be taken care of, and you're looking for a strongly typed solution, this class can help, see usage (fluent) below. It operates as either a black-list or white-list per type. A type cannot be both (Gist- also contains global ignore list).

扩展Rentering.com 的答案，在需要处理多种类型的整个图并且您正在寻找强类型解决方案的情况下，此类可以提供帮助，请参阅下面的用法（流畅）。它作为每种类型的黑名单或白名单运行。类型不能同时是（Gist- 还包含全局忽略列表）。

public class PropertyFilterResolver : DefaultContractResolver
{
  const string _Err = "A type can be either in the include list or the ignore list.";
  Dictionary<Type, IEnumerable<string>> _IgnorePropertiesMap = new Dictionary<Type, IEnumerable<string>>();
  Dictionary<Type, IEnumerable<string>> _IncludePropertiesMap = new Dictionary<Type, IEnumerable<string>>();
  public PropertyFilterResolver SetIgnoredProperties<T>(params Expression<Func<T, object>>[] propertyAccessors)
  {
    if (propertyAccessors == null) return this;

    if (_IncludePropertiesMap.ContainsKey(typeof(T))) throw new ArgumentException(_Err);

    var properties = propertyAccessors.Select(GetPropertyName);
    _IgnorePropertiesMap[typeof(T)] = properties.ToArray();
    return this;
  }

  public PropertyFilterResolver SetIncludedProperties<T>(params Expression<Func<T, object>>[] propertyAccessors)
  {
    if (propertyAccessors == null)
      return this;

    if (_IgnorePropertiesMap.ContainsKey(typeof(T))) throw new ArgumentException(_Err);

    var properties = propertyAccessors.Select(GetPropertyName);
    _IncludePropertiesMap[typeof(T)] = properties.ToArray();
    return this;
  }

  protected override IList<JsonProperty> CreateProperties(Type type, MemberSerialization memberSerialization)
  {
    var properties = base.CreateProperties(type, memberSerialization);

    var isIgnoreList = _IgnorePropertiesMap.TryGetValue(type, out IEnumerable<string> map);
    if (!isIgnoreList && !_IncludePropertiesMap.TryGetValue(type, out map))
      return properties;

    Func<JsonProperty, bool> predicate = jp => map.Contains(jp.PropertyName) == !isIgnoreList;
    return properties.Where(predicate).ToArray();
  }

  string GetPropertyName<TSource, TProperty>(
  Expression<Func<TSource, TProperty>> propertyLambda)
  {
    if (!(propertyLambda.Body is MemberExpression member))
      throw new ArgumentException($"Expression '{propertyLambda}' refers to a method, not a property.");

    if (!(member.Member is PropertyInfo propInfo))
      throw new ArgumentException($"Expression '{propertyLambda}' refers to a field, not a property.");

    var type = typeof(TSource);
    if (!type.GetTypeInfo().IsAssignableFrom(propInfo.DeclaringType.GetTypeInfo()))
      throw new ArgumentException($"Expresion '{propertyLambda}' refers to a property that is not from type '{type}'.");

    return propInfo.Name;
  }
}

Usage:

用法：

var resolver = new PropertyFilterResolver()
  .SetIncludedProperties<User>(
    u => u.Id, 
    u => u.UnitId)
  .SetIgnoredProperties<Person>(
    r => r.Responders)
  .SetIncludedProperties<Blog>(
    b => b.Id)
  .Ignore(nameof(IChangeTracking.IsChanged)); //see gist

回答by Jovie

I am using JsonProperty attributes when serializing but ignoring them when deserializing using this ContractResolver:

我在序列化时使用 JsonProperty 属性，但在使用此反序列化时忽略它们ContractResolver：

public class IgnoreJsonPropertyContractResolver: DefaultContractResolver
    {
        protected override IList<JsonProperty> CreateProperties(Type type, MemberSerialization memberSerialization)
        {
            var properties = base.CreateProperties(type, memberSerialization);
            foreach (var p in properties) { p.PropertyName = p.UnderlyingName; }
            return properties;
        }
    }

The ContractResolverjust sets every property back to the class property name (simplified from Shimmy's solution). Usage:

在ContractResolver刚刚设置每个属性回类属性的名称（从摆振的解决方案简化）。用法：

var airplane= JsonConvert.DeserializeObject<Airplane>(json, 
    new JsonSerializerSettings { ContractResolver = new IgnoreJsonPropertyContractResolver() });