向 Python 模块动态添加函数
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/1621350/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
dynamically adding functions to a Python module
提问by AnC
Our framework requires wrapping certain functions in some ugly boilerplate code:
我们的框架需要将某些功能包装在一些丑陋的样板代码中：
def prefix_myname_suffix(obj):
def actual():
print 'hello world'
obj.register(actual)
return obj
I figured this might be simplified with a decorator:
我认为这可以通过装饰器来简化：
@register
def myname():
print 'hello world'
However, that turned out to be rather tricky, mainly because the framework looks for a certain pattern of function names at module level.
然而，结果证明这相当棘手，主要是因为框架在模块级别寻找特定的函数名称模式。
I've tried the following within the decorator, to no avail:
我在装饰器中尝试了以下操作，但无济于事：
current_module = __import__(__name__)
new_name = prefix + func.__name__ + suffix
# method A
current_module[new_name] = func
# method B
func.__name__ = new_name
current_module += func
Any help would be appreciated!
任何帮助，将不胜感激！
回答by Oren S
use either
使用
current_module.new_name = func
or
或者
setattr(current_module, new_name, func)
回答by truppo
It seems the solution to your problem would be to make the decorated function act as the original function.
您的问题的解决方案似乎是使装饰函数充当原始函数。
Try using the function mergeFunctionMetadatafrom Twisted, found here:
twisted/python/util.py
尝试使用mergeFunctionMetadataTwisted 中的函数，在此处找到：
twisted/python/util.py
It makes your decorated function act as the original, hopefully making the framework pick it up.
它使您的装饰函数充当原始函数，希望使框架能够接收它。
