java 迭代 ArrayList 的通用类型<用户>
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Iterate Generic type<User> of ArrayList
提问by Mdhar9e
I am trying to get the values from an arraylist.
我正在尝试从数组列表中获取值。
I have the User type bean class as below..
我有 User 类型 bean 类，如下所示..
class User{
public String link;
public String url;
User(String l,String u){
this.link=link;
this.url=url;
}
setters and getters below..
Here I am trying to write a class with main.
在这里，我试图用 main 编写一个类。
public class ListClass{
public static void main(String args[]){
List<User> list = new ArrayList<User>();
list.add(new User("link1","url1"));
list.add(new User("link2","url2"));
list.add(new User("link3","url3"));
//here i want to iterate both links and urls one by one
Iterator it=list.iterator();
// remaining the code to get both link1 and url1 ..
}
I need the output as:
我需要输出为：
link1 url1
link2 url2
link3 url2
回答by Alexander Pavlov
You can use the for-in construct instead of the Iterator:
您可以使用 for-in 构造而不是 Iterator：
for (User u : list) {
System.out.println(u.link + " " + u.url);
}
If you definitely want to use the iterator:
如果您确实想使用迭代器：
Iterator<User> it=list.iterator();
while (it.hasNext()) {
User u = it.next();
System.out.println(u.link + " " + u.url);
}
回答by hmjd
As has already been stated by other users you can use the enhanced forstatement. Consider also adding a toString()implementation for User:
正如其他用户已经声明的那样，您可以使用增强for声明。还考虑添加一个toString()实现User：
class User
{
@Override public String toString()
{
return this.link + " " + this.url;
}
}
which would reduce the loop to:
这会将循环减少到：
for (User u: list)
{
System.out.println(u);
}
回答by Jeremy Goodell
for (User u : list) {
System.out.println(u.getLink() + " " + u.getUrl());
}
回答by Edwin Dalorzo
And if you insist with itereator:
如果你坚持使用迭代器：
Iterator<User> it = list.iterator();
while(it.hasNext()) {
/...
it.next();
}
