php 日期减去 1 年？
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Date minus 1 year?
提问by ajsie
I've got a date in this format:
我有一个这种格式的日期：
2009-01-01
How do I return the same date but 1 year earlier?
如何返回相同的日期但早于 1 年？
回答by CMS
回答by Alex
Use strtotime() function:
使用 strtotime() 函数：
$time = strtotime("-1 year", time());
$date = date("Y-m-d", $time);
回答by darrenwh
Using the DateTime object...
使用 DateTime 对象...
$time = new DateTime('2099-01-01');
$newtime = $time->modify('-1 year')->format('Y-m-d');
Or using now for today
或者现在使用今天
$time = new DateTime('now');
$newtime = $time->modify('-1 year')->format('Y-m-d');
回答by saadk
an easiest way which i used and worked well
我使用并运行良好的最简单方法
date('Y-m-d', strtotime('-1 year'));
this worked perfect.. hope this will help someone else too.. :)
这很完美..希望这也能帮助其他人..:)
回答by Nirmal
// set your date here
$mydate = "2009-01-01";
/* strtotime accepts two parameters.
The first parameter tells what it should compute.
The second parameter defines what source date it should use. */
$lastyear = strtotime("-1 year", strtotime($mydate));
// format and display the computed date
echo date("Y-m-d", $lastyear);
回答by Meloman
On my website, to check if registering people is 18 years old, I simply used the following :
在我的网站上，为了检查注册人是否年满 18 岁，我简单地使用了以下内容：
$legalAge = date('Y-m-d', strtotime('-18 year'));
After, only compare the the two dates.
之后，只比较两个日期。
Hope it could help someone.
希望它可以帮助某人。
回答by Oliver Tappin
Although there are many acceptable answers in response to this question, I don't see any examples of the submethod using the \Datetimeobject: https://www.php.net/manual/en/datetime.sub.php
尽管对此问题有许多可接受的答案，但我没有看到任何sub使用该\Datetime对象的方法示例：https: //www.php.net/manual/en/datetime.sub.php
So, for reference, you can also use a \DateIntervalto modify a \Datetimeobject:
因此，作为参考，您还可以使用 a\DateInterval来修改\Datetime对象：
$date = new \DateTime('2009-01-01');
$date->sub(new \DateInterval('P1Y'));
echo $date->format('Y-m-d');
Which returns:
返回：
2008-01-01
For more information about \DateInterval, refer to the documentation: https://www.php.net/manual/en/class.dateinterval.php
有关 的更多信息\DateInterval，请参阅文档：https: //www.php.net/manual/en/class.dateinterval.php
回答by Oliver Tappin
You can use the following function to subtract 1 or any years from a date.
您可以使用以下函数从日期中减去 1 年或任何年份。
function yearstodate($years) {
$now = date("Y-m-d");
$now = explode('-', $now);
$year = $now[0];
$month = $now[1];
$day = $now[2];
$converted_year = $year - $years;
echo $now = $converted_year."-".$month."-".$day;
}
$number_to_subtract = "1";
echo yearstodate($number_to_subtract);
And looking at above examples you can also use the following
查看上面的示例，您还可以使用以下内容
$user_age_min = "-"."1";
echo date('Y-m-d', strtotime($user_age_min.'year'));
