时间:2019-05-11 标签:c++intswitch

声明:本页面是StackOverFlow热门问题的中英对照翻译,遵循CC BY-SA 4.0协议,如果您需要使用它,必须同样遵循CC BY-SA许可,注明原文地址和作者信息,同时你必须将它归于原作者(不是我):StackOverFlow 原文地址: http://stackoverflow.com/questions/22028314/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me): StackOverFlow

提示:将鼠标放在中文语句上可以显示对应的英文。显示中英文
时间:2020-08-27 23:54:11  来源:igfitidea点击:

c++ int switch statement

c++switch-statement

提问by Jose Meza

i have been working on a switch for integers for the last hour and a half now, i know how to do switch with char but this seems much hard for me.any advice will be appreciated.the problem i have is that i cant accept grades over 100 which this switch currently does

在过去的一个半小时里,我一直在研究整数转换,我知道如何用字符转换,但这对我来说似乎很难。任何建议将不胜感激。我的问题是我不能接受成绩此开关当前执行的 100 多个

    int testScore;                     
    cout <<"Enter your test score and I will tell you \n";
    cout <<"the letter grade you earned ";
    cin >> testScore;

    switch(testScore/10)
{ 
    case 10:
    case 9:
        cout <<"Your grade is A.\n";
    break;
    case 8: 
        cout <<"Your grade is B.\n";
    break;
    case 7: 
        cout <<"Your grade is C.\n";
        break;
    case 6: 
            cout << "Your grade is D.\n";
        break;
    case 5: 
            cout << "Your grade is F.\n";
        break;

    default:
        cout << "That score isn't valid\n";

    }

回答by Seyon

You're dividing by 10.0, which is a double and this will not compile. This has to be changed to 10. Also, you should precede the switch statement with an if statement that checks if it's in a valid range.

你除以 10.0,这是一个双倍,这不会编译。这必须更改为 10。此外,您应该在 switch 语句之前使用 if 语句来检查它是否在有效范围内。

#include<iostream>
#include<iomanip>
using namespace std;
int main() 
{

int testScore;
cout <<"Enter your test score and I will tell you \n";
cout <<"the letter grade you earned \n";
cin >> testScore;

if (testScore<=100 && testScore>=0)
    switch(testScore/10)
    {
        case 10:
        case 9:
            cout <<"Your grade is A.\n";
            break;
        case 8:
            cout <<"Your grade is B.\n";
            break;
        case 7:
            cout <<"Your grade is C.\n";
            break;
        case 6:
            cout << "Your grade is D.\n";
            break;
        case 5:
            cout << "Your grade is F.\n";
            break;

        default:
            cout << "That score isn't valid\n";
    }
else
    cout <<"That score isn't valid\n";

return 0;
}

回答by Chris

You really should do this with 'if' not a 'switch'. Something like the following code (not tested):

你真的应该用'if'而不是'switch'来做到这一点。类似于以下代码(未测试):

if (testScore >=0 && testScore <= 100)
{
    char grade;

    if (testScore >= 90)
        grade = 'A';
    else if (testScore >= 80)
        grade = 'B';
    else if (testScore >= 70)
        grade = 'C';
    else if (testScore >= 60)
        grade = 'D';
    else
        grade = 'F';

    cout << "Your grade is " << grade << endl;
}
else
{
    cout << "Score of " << testScore << " is not valid" << endl;
}

回答by Jose Meza

i just decided to do it this way, thanks for all your answers

我只是决定这样做,感谢您的所有回答

int testScore;                     
    cout <<"Enter your test score and I will tell you \n";
    cout <<"the letter grade you earned ";
    cin >> testScore;

if (testScore >= 0 && testScore <=100)
{

        switch(testScore/10)
    { 
        case 10:
        case 9:
            cout <<"Your grade is A.\n";
        break;
        case 8: 
            cout <<"Your grade is B.\n";
        break;
        case 7: 
            cout <<"Your grade is C.\n";
            break;
        case 6: 
                cout << "Your grade is D.\n";
            break;
        default: 
                cout << "Your grade is F.\n";

        }

}

else 
    cout <<"That score isn't valid" << endl;