C语言 将 ASCII 码转换为字符值
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Converting ASCII code to a character value
提问by alexeidebono
I've just started learning how to program in C and I'm trying to make a program that accepts a number and uses it as an ASCII value to return the ASCII character associated with that value.
我刚刚开始学习如何用 C 编程，我正在尝试制作一个接受数字并将其用作 ASCII 值的程序，以返回与该值关联的 ASCII 字符。
The program works when the parameters are predefined but when I introduce the scanf function it compiles but doesnt give me the same results.
该程序在参数预定义时工作，但是当我引入 scanf 函数时，它会编译但不会给我相同的结果。
Here is my code :
这是我的代码：
#include <stdio.h>
int main(void)
{
question2();
return 0;
}
int question2(void)
{
int myInt = 65;
scanf("%d", myInt);
char ch = myInt;
printf("%c",ch);
return 0;
}
Cheers and thanks for any help guys.
干杯和感谢任何帮助家伙。
回答by hmjd
You need to pass the addressof myIntto scanf()(the compiler should have emitted a warning for this):
你需要通过地址的myInt到scanf()（编译器应该发出此警告）：
scanf("%d", &myInt);
You should also check the return value of scanf()to ensure myIntwas actually assigned to. scanf()returns the number of assignments made, which in this case is expected to be 1:
您还应该检查 的返回值scanf()以确保myInt实际分配给。scanf()返回所做的分配数量，在这种情况下预计为1：
if (1 == scanf("%d", &myInt))
{
}
Note that inthas a larger range values than a charso you should check that the value stored in myIntwill fitinto a char. There are macros defined in the header limits.hthat you can use to check:
请注意，int具有比 a 更大的范围值，char因此您应该检查存储在中的值myInt是否适合a char。标头limits.h中定义了宏，可用于检查：
if (1 == scanf("%d", &myInt))
{
if (myInt >= CHAR_MIN && myInt <= CHAR_MAX)
{
printf("%c\n", (char) myInt);
}
else
{
printf("%d out-of-range: min=%d, max=%d\n",
myInt, CHAR_MIN, CHAR_MAX);
}
}
The compiler should have also emitted an implicit function declarationwarning with respect to question2(). To correct, place the definition of question2(), or a declaration for question2(), prior to main().
编译器还应该发出关于 的隐式函数声明警告question2()。要更正，请将 的定义question2()或声明放在question2()之前main()。
