jQuery：执行同步 AJAX 请求
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jQuery: Performing synchronous AJAX requests
提问by Industrial
I've done some jQuery in the past, but I am completely stuck on this. I know about the pros and cons of using synchronous ajax calls, but here it will be required.
我过去做过一些 jQuery，但我完全坚持这一点。我知道使用同步 ajax 调用的优缺点，但这里需要它。
The remote page is loaded (controlled with firebug), but no return is shown.
远程页面已加载（由萤火虫控制），但未显示返回。
What should I do different to make my function to return properly?
我应该怎么做才能使我的函数正确返回？
function getRemote() {
var remote;
$.ajax({
type: "GET",
url: remote_url,
async: false,
success : function(data) {
remote = data;
}
});
return remote;
}
回答by Dogbert
As you're making a synchronous request, that should be
当您发出同步请求时，应该是
function getRemote() {
return $.ajax({
type: "GET",
url: remote_url,
async: false
}).responseText;
}
Example - http://api.jquery.com/jQuery.ajax/#example-3
示例 - http://api.jquery.com/jQuery.ajax/#example-3
PLEASE NOTE:Setting async property to false is deprecatedand in the process of being removed (link). Many browsers including Firefox and Chrome have already started to print a warning in the console if you use this:
请注意：不推荐将 async 属性设置为 false并且正在被删除（链接）。如果你使用这个，包括 Firefox 和 Chrome 在内的许多浏览器已经开始在控制台中打印警告：
Chrome:
铬合金：
Synchronous XMLHttpRequest on the main thread is deprecated because of its detrimental effects to the end user's experience. For more help, check https://xhr.spec.whatwg.org/.
主线程上的同步 XMLHttpRequest 已被弃用，因为它会对最终用户的体验产生不利影响。如需更多帮助，请查看https://xhr.spec.whatwg.org/。
Firefox:
火狐：
Synchronous XMLHttpRequest on the main thread is deprecated because of its detrimental effects to the end user's experience. For more help http://xhr.spec.whatwg.org/
主线程上的同步 XMLHttpRequest 已被弃用，因为它会对最终用户的体验产生不利影响。如需更多帮助http://xhr.spec.whatwg.org/
回答by Jake
You're using the ajax function incorrectly. Since it's synchronous it'll return the data inline like so:
您错误地使用了 ajax 函数。由于它是同步的，它将像这样内联返回数据：
var remote = $.ajax({
type: "GET",
url: remote_url,
async: false
}).responseText;
回答by TheBrain
how remote is that url ? is it from the same domain ? the code looks okay
该网址有多远？它来自同一个域吗？代码看起来没问题
try this
尝试这个
$.ajaxSetup({async:false});
$.get(remote_url, function(data) { remote = data; });
// or
remote = $.get(remote_url).responseText;
回答by user3116547
function getRemote() {
return $.ajax({
type: "GET",
url: remote_url,
async: false,
success: function (result) {
/* if result is a JSon object */
if (result.valid)
return true;
else
return false;
}
});
}
