如何在Java中创建具有特定结构的XML文件
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How to create XML file with specific structure in Java
提问by user3438838
I would like to create XMLfile using Java.
我想XML使用Java.
My XMLfile structure:
我的XML文件结构：
<?xml version="1.0" encoding="UTF-8"?>
<CONFIGURATION>
<BROWSER>chrome</BROWSER>
<BASE>http:fut</BASE>
<ENVIRONMENT>abcd</ENVIRONMENT>
<USER>john</USER>
<PASSWORD>abcd123</PASSWORD>
<ORGANIZATION>Tim</ORGANIZATION>
<EMPLOYEE>
<EMP_NAME>Anhorn, Irene</EMP_NAME>
<ACT_DATE>20131201</ACT_DATE>
<DATE_IN>20131201</DATE_IN>
<CLOCK_IN>0800</CLOCK_IN>
<DATE_OUT>20131201</DATE_OUT>
<CLOCK_OUT>1600</CLOCK_OUT>
</EMPLOYEE>
<EMPLOYEE>
<EMP_NAME>Arlegui, Karen Jay</EMP_NAME>
<ACT_DATE>20131201</ACT_DATE>
<DATE_IN>20131201</DATE_IN>
<CLOCK_IN>1600</CLOCK_IN>
<DATE_OUT>20131202</DATE_OUT>
<CLOCK_OUT>0000</CLOCK_OUT>
</EMPLOYEE>
</CONFIGURATION>
采纳答案by Ahmad Vatani
You can use the JDOMlibrary in Java. Define your tags as Elementobjects, document your elements with Document Class, and build your xml file with SAXBuilder. Try this example:
您可以在 Java 中使用JDOM库。将您的标签定义为Element对象，使用Document Class记录您的元素，并使用SAXBuilder构建您的 xml 文件。试试这个例子：
//Root Element
Element root=new Element("CONFIGURATION");
Document doc=new Document();
//Element 1
Element child1=new Element("BROWSER");
//Element 1 Content
child1.addContent("chrome");
//Element 2
Element child2=new Element("BASE");
//Element 2 Content
child2.addContent("http:fut");
//Element 3
Element child3=new Element("EMPLOYEE");
//Element 3 --> In this case this element has another element with Content
child3.addContent(new Element("EMP_NAME").addContent("Anhorn, Irene"));
//Add it in the root Element
root.addContent(child1);
root.addContent(child2);
root.addContent(child3);
//Define root element like root
doc.setRootElement(root);
//Create the XML
XMLOutputter outter=new XMLOutputter();
outter.setFormat(Format.getPrettyFormat());
outter.output(doc, new FileWriter(new File("myxml.xml")));
回答by Ran Adler
Use JAXB: http://www.mkyong.com/java/jaxb-hello-world-example/
使用 JAXB：http: //www.mkyong.com/java/jaxb-hello-world-example/
package com.mkyong.core;
import javax.xml.bind.annotation.XmlAttribute;
import javax.xml.bind.annotation.XmlElement;
import javax.xml.bind.annotation.XmlRootElement;
@XmlRootElement
public class Customer {
String name;
int age;
int id;
public String getName() {
return name;
}
@XmlElement
public void setName(String name) {
this.name = name;
}
public int getAge() {
return age;
}
@XmlElement
public void setAge(int age) {
this.age = age;
}
public int getId() {
return id;
}
@XmlAttribute
public void setId(int id) {
this.id = id;
}
}
package com.mkyong.core;
import java.io.File;
import javax.xml.bind.JAXBContext;
import javax.xml.bind.JAXBException;
import javax.xml.bind.Marshaller;
public class JAXBExample {
public static void main(String[] args) {
Customer customer = new Customer();
customer.setId(100);
customer.setName("mkyong");
customer.setAge(29);
try {
File file = new File("C:\file.xml");
JAXBContext jaxbContext = JAXBContext.newInstance(Customer.class);
Marshaller jaxbMarshaller = jaxbContext.createMarshaller();
// output pretty printed
jaxbMarshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
jaxbMarshaller.marshal(customer, file);
jaxbMarshaller.marshal(customer, System.out);
} catch (JAXBException e) {
e.printStackTrace();
}
}
}
回答by DirkyJerky
There is no need for any External libraries, the JRE System libraries provide all you need.
不需要任何外部库，JRE 系统库提供您所需的一切。
I am infering that you have a org.w3c.dom.Documentobject you would like to write to a file
我推断您有一个org.w3c.dom.Document要写入文件的对象
To do that, you use a javax.xml.transform.Transformer:
为此，您可以使用javax.xml.transform.Transformer：
import org.w3c.dom.Document
import javax.xml.transform.Transformer;
import javax.xml.transform.TransformerFactory;
import javax.xml.transform.TransformerException;
import javax.xml.transform.TransformerConfigurationException;
import javax.xml.transform.dom.DOMSource;
import javax.xml.transform.stream.StreamResult;
public class XMLWriter {
public static void writeDocumentToFile(Document document, File file) {
// Make a transformer factory to create the Transformer
TransformerFactory tFactory = TransformerFactory.newInstance();
// Make the Transformer
Transformer transformer = tFactory.newTransformer();
// Mark the document as a DOM (XML) source
DOMSource source = new DOMSource(document);
// Say where we want the XML to go
StreamResult result = new StreamResult(file);
// Write the XML to file
transformer.transform(source, result);
}
}
Source: http://docs.oracle.com/javaee/1.4/tutorial/doc/JAXPXSLT4.html
来源：http: //docs.oracle.com/javaee/1.4/tutorial/doc/JAXPXSLT4.html
回答by Tamil veera Cholan
public static void main(String[] args) {
try {
DocumentBuilderFactory docFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder docBuilder = docFactory.newDocumentBuilder();
Document doc = docBuilder.newDocument();
Element rootElement = doc.createElement("CONFIGURATION");
doc.appendChild(rootElement);
Element browser = doc.createElement("BROWSER");
browser.appendChild(doc.createTextNode("chrome"));
rootElement.appendChild(browser);
Element base = doc.createElement("BASE");
base.appendChild(doc.createTextNode("http:fut"));
rootElement.appendChild(base);
Element employee = doc.createElement("EMPLOYEE");
rootElement.appendChild(employee);
Element empName = doc.createElement("EMP_NAME");
empName.appendChild(doc.createTextNode("Anhorn, Irene"));
employee.appendChild(empName);
Element actDate = doc.createElement("ACT_DATE");
actDate.appendChild(doc.createTextNode("20131201"));
employee.appendChild(actDate);
TransformerFactory transformerFactory = TransformerFactory.newInstance();
Transformer transformer = transformerFactory.newTransformer();
DOMSource source = new DOMSource(doc);
StreamResult result = new StreamResult(new File("/Users/myXml/ScoreDetail.xml"));
transformer.transform(source, result);
System.out.println("File saved!");
} catch (ParserConfigurationException pce) {
pce.printStackTrace();
} catch (TransformerException tfe) {
tfe.printStackTrace();}}
The values in you XML is Hard coded.
XML 中的值是硬编码的。
