Python向上和向下循环
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Python Count up & Down loop
提问by NoCash4College
How can I simply transform this loop to count up from 1 to 100, and display the numbers? I'm starting to code recently. It works fine when counting down, but I can't figure out how to make it go from 1 -100
我怎样才能简单地转换这个循环从 1 到 100 计数，并显示数字？我最近开始编码。倒计时时效果很好，但我不知道如何让它从 1 -100 开始
example:
例子：
count = 100
while count > 0 :
print(count)
count = count - 1
采纳答案by Shawn Mehan
Start at 1, and change your conditional to break out when you reach 100. Add 1 each loop through.
从 1 开始，当你达到 100 时改变你的条件来突破。每次循环加 1。
count = 1
while count <= 100:
print(count)
count += 1
回答by Tofystedeth
Basically just do the opposite of what you've already got.
基本上只是做与你已经得到的相反的事情。
count = 1
while count < 101:
print(count)
count = count + 1
回答by F. Guinn
just start your count at 1, change your check statement to check if the number is less than 100, and use "count = count + 1" Should work, good luck!
只需从 1 开始计数，更改检查语句以检查数字是否小于 100，并使用 "count = count + 1" 应该可以工作，祝你好运！
回答by Nathan Ansel
If you use a for loop it gets really easy:
如果您使用 for 循环，它会变得非常简单：
for number in range(1,101):
print(number)
And for going from 100 down to 1:
从 100 降到 1：
for number in range(100,0,-1):
print(number)
回答by user1519166
Can try 'reversed':
可以尝试“反转”：
>>> for i in reversed(range(1,11)):
... print i
...
10
9
8
7
6
5
4
3
2
1
回答by Etherhead
Try this.
尝试这个。
count = 0
while count <= 100:
print ("Count = ", count)
count = count + 1
