xcode 命名空间“std”中没有名为“atomic”的类型
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No type named 'atomic' in namespace 'std'
提问by Hobbyist
Why doesn't
为什么不
std::atomic<int> index;
Work?
工作？
Currently using LLVM 3.1 with these params
当前使用带有这些参数的 LLVM 3.1
C Language Dialect GNU [-std=gnu99]
C++ Language Dialect [-std=c++11]
C++ Standard Library libc++(LLVM C++ standard library with C++11 support)
回答by Jesper Juhl
There are several things that need to be true for your code to work:
有几件事情需要你的代码才能工作：
You need to
#include <atomic>You need to compile the code as C++11 or C++14 (
-std=c++11or-std=c++14(orc++0xfor older compilers))Your compiler and standard library needs to support enough of C++11 to provide
atomic(http://clang.llvm.org/cxx_status.html)
你需要
#include <atomic>您需要将代码编译为 C++11 或 C++14（
-std=c++11或-std=c++14（或c++0x对于较旧的编译器））你的编译器和标准库需要支持足够的 C++11 来提供
atomic（http://clang.llvm.org/cxx_status.html）
回答by tamtam
Adding -std=c++11to CXXFLAGS in my Makefile -> that works for me!
-std=c++11在我的 Makefile 中添加到 CXXFLAGS -> 对我有用！
回答by 524888 Wusi
You need to write it as the following to defined variable.
您需要将其编写为以下定义的变量。
std::atomic<std::int> index;
