Java 错误：类型的非法开始
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error: illegal start of type
提问by SouvikMaji
why this little piece of code is giving illegal start of type error in line 6 and 10(for loops).... i can't find any unmatched braces...
为什么这小段代码在第 6 行和第 10 行（for 循环）中给出了类型错误的非法开始......我找不到任何不匹配的大括号......
class StackDemo{
final int size = 10;
Stack s = new Stack(size);
//Push charecters into the stack
for(int i=0; i<size; i++){
s.push((char)'A'+i);
}
//pop the stack untill its empty
for(int i=0; i<size; i++){
System.out.println("Pooped element "+i+" is "+ s.pop());
}
}
I have the class Stack implemented,
我实现了 Stack 类，
采纳答案by Ruchira Gayan Ranaweera
You can't use forloop in class level. Put them inside a methodor a block
您不能for在类级别使用循环。把它们放在 amethod或 ablock
Also java.util.Stackin Javadon't have such constructor.
同样java.util.Stack在Java没有这样的构造函数。
It should be
它应该是
Stack s = new Stack()
Another issue
另一个问题
s.push(char('A'+i))// you will get Unexpected Token error here
Just change it to
只需将其更改为
s.push('A'+i);
回答by Beri
You cannot use for loop inside a class body, you need to put them in some kind of method.
您不能在类体内使用 for 循环，您需要将它们放在某种方法中。
class StackDemo{
final int size = 10;
Stack s = new Stack(size);
public void run(){
//Push charecters into the stack
for(int i=0; i<size; i++){
s.push(char('A'+i));
}
//pop the stack untill its empty
for(int i=0; i<size; i++){
System.out.println("Pooped element "+i+" is "+ s.pop());
}
}
}
回答by Tom
You can't just write code in a class, you need a method for that:
你不能只在一个类中编写代码，你需要一个方法：
class StackDemo{
static final int size = 10;
static Stack s = new Stack(size);
public static void main(String[] args) {
//Push charecters into the stack
for(int i=0; i<size; i++){
s.push(char('A'+i));
}
//pop the stack untill its empty
for(int i=0; i<size; i++){
System.out.println("Pooped element "+i+" is "+ s.pop());
}
}
}
The method mainis the entry point for a Java application. The JVM will call that method on program startup. Please notice that I've added the code word staticto your variables, so they could be directly used in the static method main.
该方法main是 Java 应用程序的入口点。JVM 将在程序启动时调用该方法。请注意，我已将代码字添加static到您的变量中，因此它们可以直接在静态方法中使用main。
