java 使用 JAXRPC 将字符串数组作为参数发送到 Web 服务方法
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Sending array of string as a parameter to web service method using JAXRPC
提问by Anuj Balan
I've got problem sending an array of string as parameter to a web service method, given in a specific wsdl. When am trying to send an array of strings, I get the following error.
我在将字符串数组作为参数发送到特定 wsdl 中给出的 Web 服务方法时遇到问题。当我尝试发送一个字符串数组时，出现以下错误。
Error:
错误：
AxisFault
faultCode: {http://schemas.xmlsoap.org/soap/envelope/}Server.userException
faultSubcode:
faultString: org.xml.sax.SAXException: Bad types (class java.util.ArrayList >
class usdjws65.ArrayOfString)
faultActor:
faultNode:
faultDetail:
{http://xml.apache.org/axis/}hostname:SSLSPSD001
org.xml.sax.SAXException: Bad types (class java.util.ArrayList -> class usdjws65.ArrayOfString)
at org.apache.axis.message.SOAPFaultBuilder.createFault(SOAPFaultBuilder.java:222)
at org.apache.axis.message.SOAPFaultBuilder.endElement(SOAPFaultBuilder.java:129)
at org.apache.axis.encoding.DeserializationContext.endElement(DeserializationContext.java:1087)
Code written:
编写的代码：
Call call1 = objService1.createCall(port1);
call1.setTargetEndpointAddress(targetEndPoint);
call1.addParameter("int_1", XMLType.XSD_INT, Integer.class,
ParameterMode.IN);
call1.addParameter("String_1", QNAME_TYPE_STRING, ParameterMode.IN);
call1.addParameter("String_2", QNAME_TYPE_STRING_ARRAY,
java.lang.String[].class, ParameterMode.IN);
call1.addParameter("String_3", QNAME_TYPE_STRING_ARRAY,
java.lang.String[].class, ParameterMode.IN);
call1.addParameter("String_4", QNAME_TYPE_STRING, ParameterMode.IN);
call1.addParameter("String_5", QNAME_TYPE_STRING_ARRAY,
java.lang.String[].class, ParameterMode.IN);
call1.addParameter("String_6", QNAME_TYPE_STRING, ParameterMode.IN);
call1.addParameter("String_7", QNAME_TYPE_STRING, ParameterMode.IN);
// --- Done adding PARAM's
String[] attrVals = { "description", "test from soapUI",
"customer", ticketHandle, "type", "I" };
String[] attributes = { "status", "ref_num" };
Object[] params1 = { new Integer(sid), ticketHandle, attrVals, "",
"cr_tpl:400005", attributes, "", "" };
String res = null;
try {
call1.invoke(params1);
Thanks !!!! -Aj
谢谢 ！！！！-Aj
=========================================================
================================================== ========
Update-1:
更新 1：
I added a class named ArrayOfString with following code in it. protected java.lang.String[] string;
我添加了一个名为 ArrayOfString 的类，其中包含以下代码。受保护的 java.lang.String[] 字符串；
public ArrayOfString() {
}
public ArrayOfString(java.lang.String[] string) {
this.string = string;
}
public java.lang.String[] getString() {
return string;
}
public void setString(java.lang.String[] string) {
this.string = string;
}
and thus did the following, ArrayOfString attrVals = new ArrayOfString(); attrVals.setString(new String[] { "customer", "test from soapUI", "customer", ticketHandle, "type", "I" });
因此做了以下，ArrayOfString attrVals = new ArrayOfString(); attrVals.setString(new String[] { "customer", "test from soapUI", "customer", ticketHandle, "type", "I" });
Similarly, for attributes variable of type 'ArrayOfString'.
同样，对于“ArrayOfString”类型的属性变量。
But now, I get the following error::
但是现在，我收到以下错误::
AxisFault faultCode: {http://schemas.xmlsoap.org/soap/envelope/}Server.userException faultSubcode: faultString: java.io.IOException: No serializer found for class ArrayOfString in registry org.apache.axis.encoding.TypeMappingDelegate@ef2c60 faultActor: faultNode: faultDetail: {http://xml.apache.org/axis/}stackTrace:java.io.IOException: No serializer found for class ArrayOfString in registry org.apache.axis.encoding.TypeMappingDelegate@ef2c60 at org.apache.axis.encoding.SerializationContext.serializeActual(SerializationContext.java:1507) at org.apache.axis.encoding.SerializationContext.serialize(SerializationContext.java:980) at org.apache.axis.encoding.SerializationContext.outputMultiRefs(SerializationContext.java:1055) at org.apache.axis.message.SOAPBody.outputImpl(SOAPBody.java:145) at org.apache.axis.message.SOAPEnvelope.outputImpl(SOAPEnvelope.java:478) at org.apache.axis.message.MessageElement.output(MessageElement.java:1208) at org.apache.axis.client.Call.invoke(Call.java:2757) at org.apache.axis.client.Call.invoke(Call.java:2443) at org.apache.axis.client.Call.invoke(Call.java:2366) at org.apache.axis.client.Call.invoke(Call.java:1812)
AxisFault faultCode: { http://schemas.xmlsoap.org/soap/envelope/}Server.userException faultSubcode: faultString: java.io.IOException: 在注册表 org.apache.axis.encoding.TypeMappingDelegate@ 中找不到类 ArrayOfString 的序列化程序ef2c60 faultActor：faultNode：faultDetail：{ http://xml.apache.org/axis/}stackTrace:java.io.IOException: 在 org.apache.axis.encoding.SerializationContext.serializeActual(SerializationContext.java:1507) 的注册表 org.apache.axis.encoding.TypeMappingDelegate@ef2c60 中找不到类 ArrayOfString 的序列化程序。 apache.axis.encoding.SerializationContext.serialize(SerializationContext.java:980) at org.apache.axis.encoding.SerializationContext.outputMultiRefs(SerializationContext.java:1055) at org.apache.axis.message.SOAPBody.outputImpl(SOAPBody. java:145) 在 org.apache.axis.message.SOAPEnvelope.outputImpl(SOAPEnvelope.java:478) 在 org.apache.axis.message.MessageElement.output(MessageElement.java:1208) 在 org.apache.axis.client .Call.invoke(Call.java:2757) 在 org.apache.axis.client.Call.invoke(Call.java:2443) 在 org.apache.axis.client.Call.invoke(Call.java:第 2366 章
Update-2:
更新 2：
Here is an update on the problem that am facing. In the WSDL file, I found something like this,
这是有关我面临的问题的更新。在WSDL文件中，我发现了这样的东西，
complexType name="ArrayOfString"
sequence
element maxOccurs="unbounded" name="string" type="xsd:string" /
/sequence
/complexType
Well, now that am meant to use this method,
好吧，既然我打算使用这种方法，
<element name="createRequest">
<complexType>
<sequence>
<element name="sid" type="xsd:int" />
<element name="creatorHandle" type="xsd:string" />
<element name="attrVals" type="impl:ArrayOfString" />
<element name="propertyValues" type="impl:ArrayOfString" />
<element name="template" type="xsd:string" />
<element name="attributes" type="impl:ArrayOfString" />
<element name="newRequestHandle" type="xsd:string" />
<element name="newRequestNumber" type="xsd:string" />
</sequence>
</complexType>
</element>
Now, I tried sending the parameters 'attrVals','attibutes' like this
现在，我尝试像这样发送参数 'attrVals','attributes'
ArrayOfstring attrVals = new ArrayOfstring();
ArrayOfstring attributes = new ArrayOfstring();
attrVals.setString(new String[] { "customer", "test from soapUI",
"customer", ticketHandle, "type", "I" });
attributes.setString(new String[] { "status", "ref_num" });
Its throwing the following exception
它抛出以下异常
AxisFault
faultCode: {http://schemas.xmlsoap.org/soap/envelope/}Server.userException
faultSubcode:
faultString: java.io.IOException: No serializer found for class org.tempuri.complex.data.arrays.xsd.ArrayOfstring in registry org.apache.axis.encoding.TypeMappingDelegate@11e1e67
faultActor:
faultNode:
faultDetail:
{http://xml.apache.org/axis/}stackTrace:java.io.IOException: No serializer found for class org.tempuri.complex.data.arrays.xsd.ArrayOfstring in registry org.apache.axis.encoding.TypeMappingDelegate@11e1e67
at org.apache.axis.encoding.SerializationContext.serializeActual(SerializationContext.java:1507)
at org.apache.axis.encoding.SerializationContext.serialize(SerializationContext.java:980)
采纳答案by Anuj Balan
The above error has been solved. I simply registered the ArrayOfString class, String[] with the TypeRegistryMapping class. Now, it doesn't throw the above serialize error. Code edited is:
上面的错误已经解决了。我只是用 TypeRegistryMapping 类注册了 ArrayOfString 类 String[]。现在，它不会抛出上述序列化错误。编辑的代码是：
ServiceFactory factory1 = ServiceFactory.newInstance();
QName qnTick = new QName("http://soapinterop.org/xsd", "ArrayOfString");
Service serviceTickReq = factory1.createService(qnTick);
// Service serviceTickReq = new org.apache.axis.client.Service();
TypeMappingRegistry tmr = (TypeMappingRegistry) serviceTickReq
.getTypeMappingRegistry();
TypeMapping tm = (TypeMapping) tmr.getDefaultTypeMapping();
tm.register(ArrayOfString.class, qnTick, new BeanSerializerFactory(
ArrayOfString.class, qnTick), new BeanDeserializerFactory(
ArrayOfString.class, qnTick));
TypeMappingRegistry tmr1 = (TypeMappingRegistry) serviceTickReq
.getTypeMappingRegistry();
TypeMapping tm1 = (TypeMapping) tmr1.getDefaultTypeMapping();
tm1.register(String[].class, qnTick, new BeanSerializerFactory(
String[].class, qnTick), new BeanDeserializerFactory(
String[].class, qnTick));
