C++ 中的预期表达式？
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expected expression in C++?
提问by user2101748
#include <iostream>
using namespace std;
void num7()
{
int numRows;
cin >> numRows;
for (int x = 0; x < numRows/2; x++) {
for (int y = 0; y <= x; y++) {
cout << "*";
}
cout << "\n";
}
float numRowsfloat = numRows;
double cos = numRowsfloat / 2;
int tan = numRowsfloat / 2;
double sin = tan;
if (cos == sin)
cout << "\n";
for (int x = 0; x < numRows/2; x++) {
for (int y = numRows/2; y >0; y--) {
cout << "*";
}
}
else
for (int x = 0; x < numRows/2+1; x++) {
for (int y = x; y >0; y--) {
cout << "*";
}
cout << "\n";
}
}
In the else column, it says expected expression. This is trying to make a triangular shape. like
在 else 列中，它表示预期的表达式。这是试图制作一个三角形。喜欢
*
**
***
***
**
*
for inputed 6 or
对于输入 6 或
*
**
***
**
*
for inputed 5
对于输入 5
回答by Some programmer dude
You problem is this:
你的问题是这样的：
if (cos == sin)
cout << "\n";
for (int x = 0; x < numRows/2; x++) {
for (int y = numRows/2; y >0; y--) {
cout << "*";
}
}
Here only the coutis part of the ifstatement. The loop is not. You need to add braces around the whole block.
这里仅cout是if声明的一部分。循环不是。您需要在整个块周围添加大括号。
回答by Tarandeep Gill
You forgot the braces for the if statement. try this:
你忘记了 if 语句的大括号。尝试这个：
if (cos == sin) {
cout << "\n";
for (int x = 0; x < numRows/2; x++) {
for (int y = numRows/2; y >0; y--) {
cout << "*";
}
}
} else
for (int x = 0; x < numRows/2+1; x++) {
for (int y = x; y >0; y--) {
cout << "*";
}
cout << "\n";
}
