如何从android google map v2中的给定地址获取纬度和经度？
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How to get latitude and longitude from a given address in android google map v2?
提问by Dheerendra Upadhyay
I am using google map v2 android and map is too displayed in my app. I just want to get latitude and longitude from a given address.
我正在使用谷歌地图 v2 android 并且地图在我的应用程序中显示太多。我只想从给定的地址获取纬度和经度。
Example: In text field if I type "Indore", then I get the latitude and longitude of this city.
示例：在文本字段中，如果我输入“Indore”，那么我会得到这个城市的纬度和经度。
回答by codeRider
You can use this method
你可以使用这个方法
public void getLatLongFromPlace(String place) {
try {
Geocoder selected_place_geocoder = new Geocoder(context);
List<Address> address;
address = selected_place_geocoder.getFromLocationName(place, 5);
if (address == null) {
d.dismiss();
} else {
Address location = address.get(0);
Latitude lat= location.getLatitude();
Longitude lng = location.getLongitude();
}
} catch (Exception e) {
e.printStackTrace();
fetchLatLongFromService fetch_latlng_from_service_abc = new fetchLatLongFromService(
place.replaceAll("\s+", ""));
fetch_latlng_from_service_abc.execute();
}
}
//Sometimes happens that device gives location = null
public class fetchLatLongFromService extends
AsyncTask<Void, Void, StringBuilder> {
String place;
public fetchLatLongFromService(String place) {
super();
this.place = place;
}
@Override
protected void onCancelled() {
// TODO Auto-generated method stub
super.onCancelled();
this.cancel(true);
}
@Override
protected StringBuilder doInBackground(Void... params) {
// TODO Auto-generated method stub
try {
HttpURLConnection conn = null;
StringBuilder jsonResults = new StringBuilder();
String googleMapUrl = "http://maps.googleapis.com/maps/api/geocode/json?address="
+ this.place + "&sensor=false";
URL url = new URL(googleMapUrl);
conn = (HttpURLConnection) url.openConnection();
InputStreamReader in = new InputStreamReader(
conn.getInputStream());
int read;
char[] buff = new char[1024];
while ((read = in.read(buff)) != -1) {
jsonResults.append(buff, 0, read);
}
String a = "";
return jsonResults;
} catch (Exception e) {
e.printStackTrace();
}
return null;
}
@Override
protected void onPostExecute(StringBuilder result) {
// TODO Auto-generated method stub
super.onPostExecute(result);
try {
JSONObject jsonObj = new JSONObject(result.toString());
JSONArray resultJsonArray = jsonObj.getJSONArray("results");
// Extract the Place descriptions from the results
// resultList = new ArrayList<String>(resultJsonArray.length());
JSONObject before_geometry_jsonObj = resultJsonArray
.getJSONObject(0);
JSONObject geometry_jsonObj = before_geometry_jsonObj
.getJSONObject("geometry");
JSONObject location_jsonObj = geometry_jsonObj
.getJSONObject("location");
String lat_helper = location_jsonObj.getString("lat");
double lat = Double.valueOf(lat_helper);
String lng_helper = location_jsonObj.getString("lng");
double lng = Double.valueOf(lng_helper);
LatLng point = new LatLng(lat, lng);
} catch (JSONException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
The usual method to find the location is the one which i had mentioned earlier but sometime the network provider or GPS provider is not able to fetch location thus gives null value,it happened with me also but when the location is null and an exception is thrown,use the google web service to fetch the lat and long.First try to fetch from the above method and if it fails which happens sometimes go with the second method to fetch it from a web service.
查找位置的常用方法是我之前提到的方法，但有时网络提供商或 GPS 提供商无法获取位置，因此给出空值，我也发生过这种情况，但是当位置为空并抛出异常时，使用谷歌网络服务获取经纬度。首先尝试从上述方法中获取，如果失败，有时会使用第二种方法从网络服务中获取它。
回答by Jitesh Upadhyay
hi please use below google api for this purpose!!
嗨，请为此使用下面的 google api ！！
http://maps.google.com/maps/api/geocode/json?address=Indore&sensor=false
http://maps.google.com/maps/api/geocode/json?address=Indore&sensor=false
you can use given below function in yours program to fetch latitude and longitude
你可以在你的程序中使用下面给出的函数来获取纬度和经度
public static void getLatLongFromGivenAddress(String youraddress) {
String uri = "http://maps.google.com/maps/api/geocode/json?address=" +
youraddress + "&sensor=false"
HttpGet httpGet = new HttpGet(uri);
HttpClient client = new DefaultHttpClient();
HttpResponse response;
StringBuilder stringBuilder = new StringBuilder();
try {
response = client.execute(httpGet);
HttpEntity entity = response.getEntity();
InputStream stream = entity.getContent();
int b;
while ((b = stream.read()) != -1) {
stringBuilder.append((char) b);
}
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
JSONObject jsonObject = new JSONObject();
try {
jsonObject = new JSONObject(stringBuilder.toString());
lng = ((JSONArray)jsonObject.get("results")).getJSONObject(0)
.getJSONObject("geometry").getJSONObject("location")
.getDouble("lng");
lat = ((JSONArray)jsonObject.get("results")).getJSONObject(0)
.getJSONObject("geometry").getJSONObject("location")
.getDouble("lat");
Log.d("latitude", lat);
Log.d("longitude", lng);
} catch (JSONException e) {
e.printStackTrace();
}
}
to check this api please visit below link
要检查这个 api 请访问下面的链接
http://maps.google.com/maps/api/geocode/json?address=Indore&sensor=false
http://maps.google.com/maps/api/geocode/json?address=Indore&sensor=false
you will get following json which you need to parse
您将获得以下需要解析的 json
{
"results" : [
{
"address_components" : [
{
"long_name" : "Indore",
"short_name" : "Indore",
"types" : [ "locality", "political" ]
},
{
"long_name" : "Indore",
"short_name" : "Indore",
"types" : [ "administrative_area_level_2", "political" ]
},
{
"long_name" : "Madhya Pradesh",
"short_name" : "MP",
"types" : [ "administrative_area_level_1", "political" ]
},
{
"long_name" : "India",
"short_name" : "IN",
"types" : [ "country", "political" ]
}
],
"formatted_address" : "Indore, Madhya Pradesh, India",
"geometry" : {
"bounds" : {
"northeast" : {
"lat" : 22.8485735,
"lng" : 75.965395
},
"southwest" : {
"lat" : 22.6076326,
"lng" : 75.7411195
}
},
"location" : {
"lat" : 22.7195687,
"lng" : 75.8577258
},
"location_type" : "APPROXIMATE",
"viewport" : {
"northeast" : {
"lat" : 22.8485735,
"lng" : 75.965395
},
"southwest" : {
"lat" : 22.6076326,
"lng" : 75.7411195
}
}
},
"types" : [ "locality", "political" ]
}
],
"status" : "OK"
}
you can do also as follows
你也可以做如下
public void getLatLongFromGivenAddress(String address)
{
double lat= 0.0, lng= 0.0;
Geocoder geoCoder = new Geocoder(this, Locale.getDefault());
try
{
List<Address> addresses = geoCoder.getFromLocationName(address , 1);
if (addresses.size() > 0)
{
GeoPoint p = new GeoPoint(
(int) (addresses.get(0).getLatitude() * 1E6),
(int) (addresses.get(0).getLongitude() * 1E6));
lat=p.getLatitudeE6()/1E6;
lng=p.getLongitudeE6()/1E6;
Log.d("Latitude", ""+lat);
Log.d("Longitude", ""+lng);
}
}
catch(Exception e)
{
e.printStackTrace();
}
}
}
回答by cYrixmorten
So far all the answers seems valid, using either the geocode API or the Geocoder object, just wanted to point you towards this: Google Geocoder service is unavaliable (Coordinates to address)
到目前为止，所有答案似乎都有效，使用地理编码 API 或地理编码器对象，只是想向您指出这一点：Google Geocoder 服务不可用（要寻址的坐标）
I do not know how frequent this problem occurs but from time to time some devices cannot use the Geocoder object, so what I did was combining both methods, falling back to the HTTP geocode API.
我不知道这个问题发生的频率有多高，但有时有些设备无法使用 Geocoder 对象，所以我所做的是将这两种方法结合起来，退回到 HTTP 地理编码 API。
Happy coding
快乐编码
回答by jitain sharma
Just use the following code and you will get what you want:
只需使用以下代码，你就会得到你想要的：
Geocoder geocoder;
List<Address> addresses;
geocoder = new Geocoder(ctx, Locale.getDefault());
addresses = geocoder.getFromLocation(location.getLatitude(), location.getLongitude(), 1);
Where 1 is the limit to get the maxResults.
其中 1 是获得 maxResults 的限制。
