Python 类型错误：“float”类型的对象没有 len()
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TypeError: object of type 'float' has no len()
提问by user3042418
Here's the error: for j in range (len(rotlati)):
这是错误：对于范围内的 j (len(rotlati))：
TypeError: object of type 'float' has no len()
类型错误：“float”类型的对象没有 len()
I have seen many other posts but I haven't found the solution yet. I'm a bit confused. Please comment if you know what's going on here.
我看过很多其他帖子，但我还没有找到解决方案。我有点困惑。如果您知道这里发生了什么，请发表评论。
The code is:
代码是：
m = 22
rlati = numpy.zeros(m)
n = 22
rlongi = numpy.zeros(n)
v = numpy.ndarray((2,),float)
for j in range (len(lati)):
LA = lati[j]
rlati[j] = LA - latiref
for i in range (len(longi)):
LO = longi[i]
rlongi[i] = LO - longiref
v[0] = rlati[j]
v[1] = rlongi[i]
vv = numpy.matrix(v)
#transpose of vv as vv.T
vv = vv.T
#proper rotation
vn = R*vv
#define how many decimals
vn = numpy.around(vn, decimals =2)
# rotation of the second column (lati) and third line (longi)
rotlati = float(vn[0])
rotlongi = float(vn[1])
s = 22
latidef = numpy.zeros(s)
p = 22
longidef = numpy.zeros(p)
for j in range (len(rotlati)):
RLA = rotlati[j]
latidef[j] = RLA + latiref
for i in range (len(rotlongi)):
RLO = rotlongi[i]
longidef[i]= RLO + longiref
RLADEF = latidef[j]
RLODEF = longidef[i]
return RLADEF, RLODEF
回答by jez
The error is exactly what is says it is. rotlatiis a float. You cannot take the len()of a float. Looking at your code, it looks as if you might have meantto create listscalled rotlatiand rotlongiand append to them on each iteration of your range(len(lati))loop. Instead you're currently just overwriting the same two floating-point variables on every iteration.
错误正是所说的那样。rotlati是一个float。您不能使用len()a 的float。查看您的代码，您似乎打算在循环的每次迭代中创建名为and 的列表并附加到它们。相反，您目前只是在每次迭代时覆盖相同的两个浮点变量。rotlatirotlongirange(len(lati))
回答by tremendows
The len argument may be a sequence (string, tuple or list) or a mapping (dictionary). https://docs.python.org/2/library/functions.html#len
len 参数可以是序列（字符串、元组或列表）或映射（字典）。 https://docs.python.org/2/library/functions.html#len
Before calling the len function, you should verify if the argument is one of this type. You can call the method isinstance() to verify it. Take a look on how to use it. https://docs.python.org/2/library/functions.html#isinstance
在调用 len 函数之前，您应该验证参数是否是这种类型之一。您可以调用方法 isinstance() 来验证它。看看如何使用它。 https://docs.python.org/2/library/functions.html#isinstance
回答by Shuai
I got the correct answer, try this:
我得到了正确的答案，试试这个：
lloyd = {
"name": "Lloyd",
"homework": [90.0, 97.0, 75.0, 92.0],
"quizzes": [88.0, 40.0, 94.0],
"tests": [75.0, 90.0]
}
alice = {
"name": "Alice",
"homework": [100.0, 92.0, 98.0, 100.0],
"quizzes": [82.0, 83.0, 91.0],
"tests": [89.0, 97.0]
}
tyler = {
"name": "Tyler",
"homework": [0.0, 87.0, 75.0, 22.0],
"quizzes": [0.0, 75.0, 78.0],
"tests": [100.0, 100.0]
}
numbers = []
def average(numbers):
total = float(sum(numbers))
return total / len(numbers)
回答by gaurav Pawar
Another scenario i got the same error, while saving file.
另一种情况，我在保存文件时遇到了同样的错误。
odf.to_excel(writer,sheet_name=str(x),startcol=5,index=False)
odf.to_excel(writer,sheet_name=str(x),startcol=5,index=False)
You may also check the name of the sheet is int or float. Convert that to string.
您还可以检查工作表的名称是 int 还是 float。将其转换为字符串。
