Javascript javascript删除字符串中所有出现的字符
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javascript delete all occurrences of a char in a string
提问by Sonnenhut
I want to delete all characters like [or ]or &in a string i.E. :
"[foo] & bar" -> "foo bar"
我想删除字符串 iE 中的所有字符，如[或]或&：“[foo] & bar”->“foo bar”
I don't want to call replace 3 times, is there an easier way than just coding:
我不想调用替换 3 次，是否有比编码更简单的方法：
var s="[foo] & bar";
var s="[foo] & bar";
s=s.replace('[','');
s=s.replace('[','');
s=s.replace(']','');
s=s.replace(']','');
s=s.replace('&','');
s=s.replace('&','');
回答by Felix Kling
Regular expressions [xkcd](I feel like him ;)):
正则表达式[xkcd]（我觉得他很像；））：
s = s.replace(/[\[\]&]+/g, '');
Reference:
参考：
Side note:
旁注：
JavaScript's replacefunction only replaces the first occurrenceof a character. So even your code would not have replaced all the characters, only the first one of each. If you want to replace all occurrences, you have to use a regular expressionwith the global modifier.
JavaScript 的replace函数只替换第一次出现的字符。因此，即使您的代码也不会替换所有字符，只会替换每个字符中的第一个。如果要替换所有出现的内容，则必须使用带有lobal 修饰符的正则表达式。g
