java 正则表达式检查字符串是否以特定字符开头和结尾
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RegEx to check if a string starts and end with a particular character
提问by Saju
I need a regular expression that checks if the string starts and end with a special character like -
我需要一个正则表达式来检查字符串是否以特殊字符开头和结尾，例如 -
%ASDF%
"ASDF"
@ASDF@
回答by Naveed S
The following regex matches strings that begin and end with the same character:
以下正则表达式匹配以相同字符开头和结尾的字符串：
(.).*
.stands for any character and enclosing is for marking a capture group so that it can be backreferenced.
.代表任何字符，封闭用于标记捕获组，以便它可以被反向引用。
.*matches zero or more characters.
.*匹配零个或多个字符。
\1backreferences the first capture group (i.e. the first character)
\1反向引用第一个捕获组（即第一个字符）
So it matches aba, #ee#, eeetc. If you require at least one character between starting and ending characters, replace the *with +.
所以它匹配ABA，＃EE＃ ，EE等，如果你需要开始和结束字符之间至少有一个字符，替换*用+。
回答by Lefteris E
^((%.+%)|(".+")|(@.+@))$
^means start of the line$means end of the line|means or.means any character+means repeated 1 or more times
^意味着行的开始$表示行尾|手段或.表示任何字符+表示重复 1 次或多次
